Answer:
The duration of the impact is 0.005384 seconds
Explanation:
Given
m = 0.43 kg
v = 5.2 m/s
x = 0.014 m
Knowing the formulas
<h3><u>Answer;</u></h3>
<u> = 55.2 Coulombs </u>
<h3><u>Explanation</u>;</h3>
We can determine Charge using the formula
Q =It, where Q is the amount of charge in Coulombs, I is the current in amperes and t is the time in seconds.
I = 0.92 amperes, t = 1 minute or 60 seconds
Charge = 0.92 × 60
<u> = 55.2 Coulombs </u>
Answer:
Option B is the correct answer.
Explanation:
Let us consider 40 meter above ground as origin.
Initial velocity = 17 m/s
Final velocity = 24 m/s
Acceleration = 9.81 m/s
We have equation of motion v² = u² + 2as
Substituting
24² = 17² + 2 x 9.81 x s
s = 14.63 m
Distance traveled by rock = 14.63 m down.
Height of rock from ground = 40 - 14.63 = 25.37 m = 25.4 m
Option B is the correct answer.
Answer:
-2.33 m/s²
Explanation:
The computation of the skateboarder’s acceleration is shown below;
Acceleration means the change in velocity per unit with respect to time.
In the given case, the initial velocity is 7 m/s.
As in the question it is mentioned that it comes to a stop, so the final velocity would be zero.
And, The time elapsed is 3 seconds.
Now the following equation should be used
a = (v,final - v,initial) ÷ t
= (0 - 7)/3
= -2.33 m/s²
KE = 1/2 * m * v2
We have to rearrange this so the subject is mass. (because the question asks for the mass of the object) :
Mass = (2 * KE) / v
Now input the values into this equation to get your answer :
Mass = (2 * KE) / v
Mass = (2 * 480) / 8
Mass = 960 / 8
Mass = 120
