Answer:b
Explanation:
Given
mass of heavy object is 4m
mass of lighter object is m
A person pushes each block with same force F
According to Work Energy theorem Change in kinetic energy of object is equal to Work done by all the object
As launching velocity is same for both the object so heavier mass must possess greater kinetic energy . For same force heavier mass must be pushed 4 times farther than the light block .


So the correct option is b
Answer:A. It is modified by the cell, so there is still more glucose on the outside of the cell than inside it
Explanation: The cells are the primary unit of a living organism,it is the place where cellular respiration takes place, which is the use of oxygen to break down food substances such as Glucose to release energy in the form of Adenosine trisphosphate (ATP) and give out Carbondioxide as a by-product of cellular respiration.
Most of the Glucose enter the cells to get modified through cellular respiration so their is still more Glucose outside than the Glucose inside.
Answer:
Noise level will be -18.2 watt
So option (b) will be correct answer
Explanation:
We have given sound intensity 
And threshold intensity
( in question it is given as
but its standard value is
)
Now noise level 
So the noise level will be -18.2
So option (b) will be correct answer