Data:
n (number of mols) = ?
V (volume) = 2.50 Liters
If:
1 L → 1000 g
2.50 L → y
y = 1000*2.50 = 2500 g
Therefore:
m (mass) = 2500 g
Now:
Molar Mass (MM) of oxygen = 16 g/mol
Formula:
Solving:
Longer, this is because the H in HNO2 is bonded with an oxygen, no longer allowing this structure to have a resonance structure.
NO2 on the other hand has one double bond and one single bond, so it has a resonance structure. And resonance structures are actually one structure so there isn't really a single and double bond, it's actually a 1 and 1/2 bond that calls for a higher bond order.
And I higher bond order will result in a shorter lengths!
I hope this helps out!!! And just out of curiosity, is this off of an AP FRQ packet??
Answer:
a) r = k × [A] × [B]²
b) 3
Explanation:
Let's consider the following generic reaction
A + B + C ⇒ Products
The generic rate law is:
r = k × [A]ᵃ × [B]ᵇ × [C]ⁿ
where
This reaction is first order in A, second order in B, and zero order in C. The rate law is:
r = k × [A]¹ × [B]² × [C]⁰
r = k × [A] × [B]²
The overall order of the reaction is the sum of the individual reaction orders.
1 + 2 + 0 = 3
Answer:
8.76M
Explanation:
Given that
Mass from the density = 1141g
According to the given situation the computation of molarity of the solution is shown below:-
we will took HCL solution which is 1000mL
HCl = 28% by mass
So,
Mass of HCl in 1-litre solution is
Which gives the result of molar mass HCI is
= 319.48g
/mol
Now,
Molarity is
Which gives results of molarity is
= 8.76M
Answer:
The density of copper is 0.5 g/mL
Explanation:
Given data:
Mass of copper = 6 g
Volume of copper = 12 mL
Density of copper = ?
Solution:
Formula:
d = m/v
d = density
m = mass
v = volume
d = 6 g/ 12 mL
d = 0.5 g/mL
Thus, the density of copper is 0.5 g/mL
