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Dafna1 [17]
3 years ago
15

As a central atom, sulfur can take more than eight electrons in its valence shell.

Chemistry
2 answers:
vladimir1956 [14]3 years ago
4 0

Answer:

true

Explanation:

vodka [1.7K]3 years ago
3 0

Sulphur is located in the third period and group 16. The general electronic configuration of group 16 is ns^{2} np^{4} therefore the maximum number of valency electrons in group 16 is 6. The electronic configuration of sulphur is [Ne] 3s^{2} 3p^{4}3d^{0}. Sulphur has six valency electrons whereas sulphur can have more than eight electrons in its valency shell as it have an empty d-shell electrons can accumulate in the empty d-shell. The complete d-shell and the P_{z} orbital will be empty. As each orbital can accept 2 electrons, sulphur can have 12 valency electrons in its valency shell.

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Net ionic equation for 2AgF(aq) + k2S = Ag2S (s) + 2KF(aq)
tester [92]

Answer:

The net ionic equation shows the actual reaction more clearly and closer to reality because it writes soluble ionic compounds as the ions and then cancel the spectator ions not involved in the chemical reaction . The net ionic equation results shows the actual chemical reaction taking place.

4 0
3 years ago
The electron in a hydrogen atom, originally in level n = 8, undergoes a transition to a lower level by emitting a photon of wave
timofeeve [1]

Explanation:

It is given that,

The electron in a hydrogen atom, originally in level n = 8, undergoes a transition to a lower level by emitting a photon of wavelength 3745 nm. It means that,

n_i=8

\lambda=3745\ nm

The amount of energy change during the transition is given by :

\Delta E=R_H[\dfrac{1}{n_f^2}-\dfrac{1}{n_i^2}]

And

\dfrac{hc}{\lambda}=R_H[\dfrac{1}{n_f^2}-\dfrac{1}{n_i^2}]

Plugging all the values we get :

\dfrac{6.63\times 10^{-34}\times 3\times 10^8}{3745\times 10^{-9}}=2.179\times 10^{-18}[\dfrac{1}{n_f^2}-\dfrac{1}{8^2}]\\\\\dfrac{5.31\times 10^{-20}}{2.179\times 10^{-18}}=[\dfrac{1}{n_f^2}-\dfrac{1}{8^2}]\\\\0.0243=[\dfrac{1}{n_f^2}-\dfrac{1}{64}]\\\\0.0243+\dfrac{1}{64}=\dfrac{1}{n_f^2}\\\\0.039925=\dfrac{1}{n_f^2}\\\\n_f^2=25\\\\n_f=5

So, the final level of the electron is 5.

4 0
3 years ago
How does the force of gravity on Jupiter compare to the force of gravity on Earth?
iogann1982 [59]

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Jupiter is the largest planet in the solar system. It is so large that all other planets would comfortably fit inside it. It is over 1000 times bigger than the earth.

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7 0
3 years ago
Question # 10
satela [25.4K]
The answer should be D, cells can only create an identical copy of the original cell.
3 0
3 years ago
Science science science science
In-s [12.5K]

Answer:

Sorry

Explanation:

Sorry this is not chemistry but I always try to answer but this time I can't I am so so sorry

4 0
3 years ago
Read 2 more answers
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