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2 years ago

The concentration of hydronium ions is greater than 1 x 10^−7 for acidic solutions. True False

Chemistry

1 answer:

Anna35 [415]2 years ago

6 0

Answer:

True.

Explanation:

Remember that hydronium ions indicate the concentration of an acid.

On the pH scale, the acids are between 0 and 7, and for bases, the pH is between 7 and 14.

The formula to calculate the pH of an acid is the following:

$pH=-log\lbrack H_3O^+].$

Now, let's replace the value of the given concentration in the formula, which is 1 x 10⁻⁷:

$pH=-log\lbrack1\cdot10^{-7}]=7.$

You can note that if the value of hydronium concentration is greater than 1 x 10⁻⁷, and we replace it in the formula, we will obtain lower pHs, which means that it is an acidic solution.

The answer would be true.

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when 45 grams of copper (ii) carbonate are decomposed with heat how many grams of carbon dioxide will be produced

Maksim231197 [3]

Answer:

16.02 g

Explanation:

the balanced equation for the decomposition of CuCO₃ is as follows

CuCO₃ --> CuO + CO₂

molar ratio of CuCO₃ to CO₂ is 1:1

number of CuCO₃ moles decomposed - 45 g / 123.5 g/mol = 0.364 mol

according to the molar ratio

1 mol of CuCO₃ decomposes to form 1 mol of CO₂

therefore 0.364 mol of CuCO₃ decomposes to form 0.364 mol of CO₂

number of CO₂ moles produced - 0.364 mol

therefore mass of CO₂ produced - 0.364 mol x 44 g/mol = 16.02 g

16.02 g of CO₂ produced

8 0

4 years ago

C12H7Cl3FNaO2 what are them elements in that chemical formula

LuckyWell [14K]

Assuming you are asking for the names of the elements in that formula , the answer is

carbon
hydrogen
chlorine
fluorine
sodium
oxygen

8 0

4 years ago

How do you convert between the mass and the number of moles of a substance?

Ksivusya [100]

To convert from grams to moles, you divide the number of grams by the molar mass To convert from moles to grams, you multiply by the molar mass. You must first calculate the molar mass of the substance

6 0

3 years ago

An equimolar mixture of acetone and ethanol is fed to an evacuated vessel and allowedto come to equilibrium at 65°C and 1.00 atm

frutty [35]

The question is incomplete, the table of the question is given below

Answer:

I) xA= 0.34, yA= 0.55

ii) 76.2 mole % vapor

iii) Percentage of vapor volume = 98%

Explanation:

i) xA= 0.34, yA= 0.55

xA= 0.34, yA= 0.55

ii) 0.50 = 0.55 nv + 0.34 nL

Therefore, nV = 0.762 mol vapor and nL = 0.238 mol liquid

This shows 76.2 mole % vapor

iii) ρA= 0.791 g/cm3 and, ρE = 0.789 g/cm3

Therefore, ρ = 0.790 g/cm3

Now, we have:

MA = 58.08 g/mol and ME= 46.07 g/mol

So Ml = (0.34 x 58.08)+[(1 -0.34) x 46.07] = 50.15 g/mol

1 mol liquid = (0.762 mol vapor/0.238 mol liquid) = 3.2 mol vapor

Liquid volume = Vl= [1 mol x (50.15 g/mol)] / (0.790 g/cm3) = 63.48 cm3

Vapour volume = Vv = 3.2 mol x(22400 cm3/mol) x [(65+273)/273] = 88747 cm3

Therefore, percentage of vapour volume = 88747 / (88747+63.48) = 99.9 %

3 0

3 years ago

What is the molar mass of Al2(SO4)3

umka21 [38]

Answer:

The molar mass of $Al_2(SO_4)_3$ is 342.145 g/mol

Explanation:

The molar mass is stated as the “mass per unit amount of substance”of a given chemical compound

$Al_2(SO_4)_3$ is Aluminium sulphate. They easily dissolve in water. It is primarily used as a 'coagulating agent' in the drinking water purification and also in waste and sewage water treatment plants,

We know,

Atomic weight of Aluminium = 26.981

Atomic weight of Sulphur= 32.065

Atomic weight of Oxygen = 15.9994

Now molar mass of $Al_2(SO_4)_3$ (Aluminium sulphate) is

=>2(26.981)+3(32.065+4(15.999))

=>53.962 +3(32.065+63.996)

=>53.962+3(96.061)

=>53.962+288.183

=>342.145

4 0

3 years ago