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viva [34]
3 years ago
10

Calculate the relative rate of effusion for the orange to blue spheres. The root-mean-square speed for the orange spheres is 565

.0 m/s. The root-mean-square speed for the blue spheres is 369.0 m/s.
Chemistry
2 answers:
Tanzania [10]3 years ago
5 0

Answer:

Relative rate of effusion for the orange to blue spheres = 1.531

Explanation:

Rate of effusion of Orange / Rate of effusion of blue = [Mblue / Morange]^1/2

Vrms = sqrt [(3RT/M)]

Vorange / Vblue = [ Mblue / Morange]^1/2

Rate of effusion of Orange / Rate of effusion of blue = 565/ 369 = 1.531

bekas [8.4K]3 years ago
4 0

Answer:

The rate of effusion of blue is 1.53 times that of orange

Explanation:

Rate of effusion of a gas at a given temperature is directly proportional to the speed of the gas and inversely proportional to their masses.

At equal temperature, two gases will have equal amount of kinetic energy.

K.E = ½mv²

K.E = 3/2 KT

MV² = 3KT

V² = 3KT / M (single molecule of a gas)

U² = 3RT /M ( mole of molecule )

3RT = MU²

RT = constant,

M1U²1 = M2U²2 for different gases at equal temperature.

Relationship between speed and rate of effusion =

m1r²1 = m2r²2 ( speed is equal to the rate of effusion)

M1 / M2 = r²2 / r²1

M(blue) / M(orange) = r²(orange) / r²(blue)

M(blue) / M(orange) = 565 / 369

M(blue) / M(orange) = 1.53

The molar mass of the blue gas is 1.53 times heavier than the orange gas.

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DedPeter [7]

Answer:

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Explanation:

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6 0
3 years ago
In a synthesis reaction you start with 1.7L of Hydrogen how many liters of water will be produced?
jolli1 [7]

15.3 litres of water will be produced if we take 1.7 litres of Hydrogen

Explanation:

Let's take a look over synthesis reaction;

H_{2}+ O_{2}<u>                         </u>H_{2}O<u />

<u>Balancing the chemical reaction;</u>

2H_{2} +O_{2}<u>                        </u>2H_{2}O<u />

Thus, 2 moles of hydrogen molecules are required to form 2 moles of water molecules.

<u>Equating the molarity;</u>

<u />\frac{1.7*1}{2*2} = \frac{x*1}{2*18}

           (Since, the molecular mass of hyd and water is 2 and 18 respectively)

x=\frac{1.7*2*18}{2*2}

x= 15.3 litres.

Thus,15.3 L of water will be produced if we take 1.7 litres of Hydrogen in a synthesis reaction.

6 0
3 years ago
A chemical engineer must calculate the maximum safe operating temperature of a high-pressure gas reaction vessel. The vessel is
Airida [17]

Answer:

the maximum safe operating temperature the engineer should recommend for this reaction is 616 °C  

Explanation:

Given the data in the question;

First we calculate the Volume of the steel cylinder;

V = πr²h

radius r = Diameter / 2 = 27 cm / 2 = 13.5 cm

height h = 32.4 cm

so we substitute

V = π × ( 13.5 cm )² × 32.4 cm

V  = π × 182.25 cm × 32.4 cm

V = 18550.79 cm³  

V = 18.551 L

given that; maximum safe pressure P = 3.10 MPa = 30.5946 atm

vessel contains 0.218kg or 218 gram of carbon monoxide gas

molar mass of carbon monoxide gas is 28.010 g/mol

so

moles of carbon monoxide gas n = 218 gram /  28.010 g/mol = 7.7829 mol

we know that;

PV = nRT

solve for T

T = PV / nR

we know that gas constant R = 0.0820574 L•atm•mol⁻¹ K⁻¹

so we substitute

T = ( 30.5946 × 18.551 ) / ( 7.7829 × 0.082 )

T = 567.5604 / 0.6381978

T = 889.317387 K

T = ( 889.317387 - 273.15 ) °C

T = 616.167 ≈ 616 °C  { 3 significant digits }

Therefore, the maximum safe operating temperature the engineer should recommend for this reaction is 616 °C  

6 0
3 years ago
A saturated solution of baso4 has a concentration of 0.5mol/l. a 55ml sample is taken by you. what is the mass of baso4 in the s
SIZIF [17.4K]

Answer:

6.4 g BaSO₄

Explanation:

You have been given the molarity and the volume of the solution. To find the mass of the solution, you need to (1) find the moles BaSO₄ (via the molarity ratio) and then (2) convert moles BaSO₄ to grams BaSO₄ (via the molar mass). It is important to arrange the conversions in a way that allows for the cancellation of units (the desired unit should be in the numerator). The final answer should have 2 sig figs to reflect the sig figs of the given values.

Molarity (mol/L) = moles / volume (L)

(Step 1)

55 mL / 1,000 = 0.055 L

Molarity = moles / volume                             <----- Molarity ratio

0.5 (mol/L) = moles / 0.055 L                        <----- Insert values

0.0275 = moles                                             <----- Multiply both sides by 0.055

(Step 2)

Molar Mass (BaSO₄): 137.33 g/mol + 32.065 g/mol + 4(15.998 g/mol)

Molar Mass (BaSO₄): 233.387 g/mol

0.0275 moles BaSO₄          233.387 g
---------------------------------  x  -------------------  =  6.4 g BaSO₄
                                                1 mole

6 0
2 years ago
The relatively high boiling point of water is due to water having
Verizon [17]
The answer should be hydrogen bonding. Water only has oxygen and hydrogen in it, which are both nonmetals, so you know the answer cannot be metallic or ionic. It also cannot be nonpolar because the electronegativity of the oxygens will make the molecule polar. You can also know it is hydrogen bonding because it can only take place when a hydrogen is attached to an oxygen, fluorine, or nitrogen. These bonds are very strong attractions, so the molecules are extremely hard to pull apart, creating a high boiling point. Hope that helps!
3 0
3 years ago
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