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Misha Larkins [42]
3 years ago
7

How well did tossing the pennies simulate half lives?

Chemistry
1 answer:
SSSSS [86.1K]3 years ago
5 0
Its a 50% chance that approx 1/2 of the pennies will land on tails. The next toss will result the same. and so on and so on. showing how a reaction would slowly eliminate 1/2 of the remaining lives per reaction, until nothing is left. I think it is a good stimulation.
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The hydrolysis of esters in base is called ________. a. the hunsdiecker reaction b. transesterification c. saponification d. the
KengaRu [80]

The hydrolysis of esters in base is called saponification .

So, option C is correct one.

The saponification is the process that involves conversion of fats , oils , lipids into soap and water in the presence of alkaline medium. Saponification is the process of making soap.

During the saponification process, the mixture has an acidity, which tells that it's not safe for usage. After the saponification process is complete, the pH should be a base.The process of formation of carboxylic salt and water by hydrolysis of ester in base is called saponification.

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2 years ago
What is two or more atoms chemically bonded together?
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i belive its molecule

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Why does alka seltzer dissolve faster in hot water?
Olenka [21]

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The higher the temperature the faster the molecules move, this means that the water moleceules will mix with the Alka-Seltzer faster.

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2 years ago
Trade in the British Empire and new inventions lead to
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<span>B. the birth of the Industrial Revolution.

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3 years ago
Give the equation: 2K + 2H2O --&gt; 2KOH + H2 If 23.5 grams of potassium are reacted with excess water, how many grams of Hydrog
Anuta_ua [19.1K]

Answers:

0.606 g H₂

Step-by-step explanation:

We know we will need a balanced equation with masses and molar masses, so let’s gather all the information in one place.  

M_r:   39.10                            2.016

           2K + 2H₂O ⟶ 2KOH + H₂

m/g:   23.5

(a) Calculate the <em>moles of K </em>

n = 23.5 g K × 1 mol K /39.10 g K

n = 0.6010 mol K

(b) Calculate the moles of H₂

The molar ratio is (1 mol H₂/2 mol K)

n = 0.6010 mol K × (1 mol H₂/2 mol K)

n = 0.3005 mol H₂

(c) Calculate the <em>mass of H₂</em>

m = 0.3005 mol H₂ × (2.016 g H₂/1 mol H₂)

m = 0.606 g H₂

5 0
3 years ago
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