Given what we know, we can confirm that hair gel is considered a noncrystalline solid due to Atoms in the hair gel having no particular order or pattern.
<h3>What is a noncrystalline solid?</h3>
- This is a solid whose atoms are amorphous.
- What this means is that the atoms lack a specific order like most solids.
- The most common example of this is glass.
Therefore, given the definition of a noncrystalline solid as a solid whose atoms lack a specified order, we can confirm that the second option which states that "Atoms in the hair gel having no particular order or pattern" is correct.
To learn more about Atoms visit:
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Answer:
1.44 g
Explanation:
The problem gives you the molarity and volume of the target solution, so right from the start you know that you can use that information to determine the number of moles of hydrochloric acid that it must contain.
So, molarity measures a solution's concentration in terms of how many moles of solute, which in your case is hydrochloric acid, you get per liter of solution.
A
0.158 M
hydrochloric acid solution contains
0.158
moles of hydrochloric acid for very liter of solution. Since you're dealing with
250 mL
, the equivalent of
1
4
th
of a liter, your solution will contain
250
mL
⋅
1
L
10
3
mL
⋅
0.158 moles HCl
1
L
=
0.0395 moles HCl
Now that you know how many moles of hydrochloric acid are needed to prepare your solution, use the compound's molar mass to convert this to grams
0.0395
moles HCl
⋅
36.46 g
1
mole HCl
=
∣
∣
∣
∣
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
a
a
1.44 g
a
a
∣
∣
−−−−−−−−−−
Explanation:
Please brainliest.
Answer: " <span>1.8 * 10²⁴ molecules of O₂ " .
________________________________________</span>
3.0 moles O₂ * (6.02 * 10²³ molecules O₂ / 1 mol O₂) =
[ (3.0) *(6.02 * 10²³) ] molecules O₂
= 1.806 * 10²⁴ ; round to 2 significant figures.
= 1.8 * 10²⁴ molecules of O₂ .
______________________________________________________
Answer:
it is not D!! i took the test and it was wrong on plato
Explanation:
Answer:
energy
Explanation:
The amount of energy carried by a wave is related to the amplitude in waves.