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Zigmanuir [339]
3 years ago
9

Which of the following is an accurate conversion of liquid to solid volume? one liter equals one cubic meter 1000 milliliters eq

ual one cubic meter 1000 liters equal one cubic meter one liter equals 1000 cubic meter
Chemistry
2 answers:
Maslowich3 years ago
8 0

Answer is: 1000 liters equal one cubic meter.

1) V = 1L.

V = 1 L ÷ 1000 L/m³.

V = 0.001 m³; one liter is equal one thousandth of cubic meter, so example 1 (one liter equals one cubic meter) is not correct.

2) V = 1000 mL.

V = 1000 mL ÷ 1000 mL/L = 1 L.

V = 1L = 0.001 m³; example 2 (1000 milliliters equal one cubic meter) is not correct.

3) V = 1000L.

V = 1000 L ÷ 1000 L/m³.

V = 1 m³; example 3 (1000 liters equal one cubic meter) is correct.

4) V = 1 L.

V = 1L.

V = 1 L ÷ 1000 L/m³.

V = 0.001 m³; one liter is equal one thousandth of cubic meter, so example 4 (one liter equals 1000 cubic meter) is not correct.

vagabundo [1.1K]3 years ago
7 0

1000 liters equal one cubic meter

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4 years ago
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One of the radioactive isotopes used in medical treatment or analysis is chromium-51. The half-life of chromium-51 is 28 days. H
Goryan [66]

Answer : The time required for decay is, 84 days.

Explanation :

Half-life of chromium-51 = 28 days

First we have to calculate the rate constant, we use the formula :

k=\frac{0.693}{t_{1/2}}

k=\frac{0.693}{28\text{ days}}

k=0.0248\text{ days}^{-1}

Now we have to calculate the time required for decay.

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant

t = time taken by sample = ?

a = let initial activity of the sample = 100

a - x = amount left after decay process  = 12.5

Now put all the given values in above equation, we get

t=\frac{2.303}{0.0248}\log\frac{100}{12.5}

t=83.9\text{ days}\approx 84\text{ days}

Therefore, the time required for decay is, 84 days.

7 0
3 years ago
Calculate the ph of a solution formed by mixing 200.0 ml of 0.30 m hclo with 300.0 ml of 0.20 m kclo. the ka for hclo is 2.9 × 1
masha68 [24]

Answer:

The pH of the solution will be 7.53.

Explanation:

Dissociation constant of KClO=K_a=2.8\times 10^{-8}

Concentration of acid in 1 l= 0.30 M

Then in 200 ml = 0.30 M\times 0.200 L=0.06 M

The concentration of acid, HClO=[acid]= 0.006 M

Concentration of salt in 1 L = 0.20 M

Then in 300 ml = 0.20 M\times 0.300 L=0.06 M

The concentration of acid, KClO=[salt]= 0.006 M

The pH of the solution will be given by formula :

pH=pK_{a}^o+\log\frac{[salt]}{[acid]}

pH=-\log[2.8\times 10^{-8}]+\frac{[0.06 M]}{[0.06 M]}

The pH of the solution will be 7.53.

4 0
3 years ago
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You know that 8.9 moles of solute particles are dissolved in that liquid solution. If the molarity of the solution is 25 M, how
pychu [463]

Answer:

V = 0.356 L

Explanation:

In this case, we need to use the following expression:

M = n/V (1)

Where:

M: molarity of solution (mol/L or M)

n: moles of solute (moles)

V: Volume of solution (Liters)

From these expression, we can solve for V:

V = n/M  (2)

Now, replacing the given data we can solve V:

V = 8.9 / 25

V = 0.356 L

5 0
3 years ago
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