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alexgriva [62]
2 years ago
11

If lon X has a charge of 2+ and lon Y has a charge of 1-, the chemical the formula of the ionic

Chemistry
1 answer:
Monica [59]2 years ago
7 0

The chemical formula of the ionic compound is XY₂.

<h3>Ionic compounds</h3>
  • Ionic compounds are compounds which are formed from the combination of negatively charged and positively charged ion.
  • Positively charged ions are formed by loss of electrons
  • Negatively-charged ions are formed from gain of electrons

<h3>Formation of ionic compounds</h3>

During the formation of the ionic compound between an ion X that has a charge of 2+ and ion Y has a charge of 1-, two negatively charged ions of Y are required to form a neutral ionic ionic compound when they react with X.

The chemical the formula of the ionic compound they form is as follows;

X²⁺  + 2Y⁻ ---> XY₂

Therefore, the chemical formula of the ionic compound is XY₂.

Learn  more about ionic compounds at: brainly.com/question/13439771

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Answer:- [Na_2CO_3]=0.254M , [Na^+]=0.508 M , [CO_3^2^-]=0.254M

Solution:- We are asked to calculate the molarity of sodium carbonate solution as well as the sodium and carbonate ions.

Molarity is moles of solute per liter of solution. We have been given with 6.73 grams of sodium carbonate and the volume of solution is 250.mL.  Grams are converted to moles and mL are converted to L and finally the moles are divided by liters to get the molarity of sodium carbonate.

Molar mass of sodium carbonate is 105.99 gram per mol. The calculations for the molarity of sodium carbonate are shown below:

\frac{6.73gNa_2CO_3}{250.mL}(\frac{1mol}{105.99g})(\frac{1000mL}{1L})

= 0.254MNa_2CO_3

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sodium carbonate dissociate to give the ions as:

Na_2CO_3(aq)\rightarrow 2Na^+(aq)+CO_3^2^-

There is 1:2 mol ratio between sodium carbonate and sodium ion. So, the molarity of sodium ion will be two times of sodium carbonate molarity.

[Na^+]=2(0.254M) = 0.508 M

There is 1:1 mol ratio between sodium carbonate and carbonate ion. So, the molarity of carbonate ion will be equal to the molarity of sodium carbonate.

[CO_3^2^-]=0.254M


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