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RUDIKE [14]
3 years ago
9

At what temperature would a 1.30 m NaCl solution freeze, given that the van't Hoff factor for NaCl is 1.9? Kf for water is 1.86

∘C/m .
Chemistry
1 answer:
Setler [38]3 years ago
4 0

Answer:

-4.59°C

Explanation:

Let's see the formula for freezing point depression.

ΔT = Kf . m . i

ΔT = Freezing T° of pure solvent - Freezing T° of solution

Kf = Freezing constant. For water if 1.86°C/m

m = molality (moles of solute in 1kg of solvent)

i = Van't Hoff factor.

0°C - Freezing T° of solution = 1.86°C /m . 1.30m . 1.9

Freezing T° of solution = - (1.86°C /m . 1.30m . 1.9)

Freezing T° of solution = - (1.86°C/m .  1.30m . 1.9) → -4.59°C

NaCl →  Na⁺  +  Cl⁻

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7 0
3 years ago
7. Use the concepts of relative abundance and relative weight to explain why carbon has an atomic mass of 12.011 amu when there
Dvinal [7]

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Extracted from" Atomic weights of the elements 2009 (IUPAC Technical Report)"

5 0
3 years ago
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Answer:

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Transition metals have high densities which increases down the group. However, the increase in density of transition elements of group 12 varies with temperature at a rate that is quite different from other transition elements. Hence the differences in the value of melting points and density changes by only a very small amount as you come down group 12 compared to other groups of transition elements.

6 0
4 years ago
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Agata [3.3K]

Answer:

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