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RUDIKE [14]
3 years ago
9

At what temperature would a 1.30 m NaCl solution freeze, given that the van't Hoff factor for NaCl is 1.9? Kf for water is 1.86

∘C/m .
Chemistry
1 answer:
Setler [38]3 years ago
4 0

Answer:

-4.59°C

Explanation:

Let's see the formula for freezing point depression.

ΔT = Kf . m . i

ΔT = Freezing T° of pure solvent - Freezing T° of solution

Kf = Freezing constant. For water if 1.86°C/m

m = molality (moles of solute in 1kg of solvent)

i = Van't Hoff factor.

0°C - Freezing T° of solution = 1.86°C /m . 1.30m . 1.9

Freezing T° of solution = - (1.86°C /m . 1.30m . 1.9)

Freezing T° of solution = - (1.86°C/m .  1.30m . 1.9) → -4.59°C

NaCl →  Na⁺  +  Cl⁻

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andre [41]

Answer:

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Explanation:

The animal is consuming the carbon present in the molecules stored in the grass. Plants process the carbon present in the soil along with other minerals. The animal, when it feeds on these plants, is consuming the carbon they obtained from the soil. Grasslands are defined largely by their use for grazing, which includes between 10 and 30 percent of soil carbon worldwide.

Have a nice day!

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3 years ago
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finlep [7]

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The <em>Law of Conservation of Mass</em> says that <em>you can’t turn matter into nothing</em>. What must be happening is that the wick and the wax are changing into other substances that we can’t see, such as colourless gases of carbon dioxide and water vapour.

5 0
3 years ago
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Andrew [12]
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a person running a car parked in a driveway

Explanation:

A person running a car parked in a driveway is an example of translational kinetic energy.

Translational motion is the movement of body along a straight path.

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learn more:

Translational kinetic energy brainly.com/question/9924094

#learnwithBrainly

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