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kolezko [41]
3 years ago
11

Calculate the percent composition of chlorine in methyl trichloride, CHCl3.

Chemistry
1 answer:
vovikov84 [41]3 years ago
5 0

Answer:

Chlorine --> 89%

Explanation:

Step 1) Add each element's amu up to get the total mass of the compound.

12.011+1.008+3(35.453) = 119.378.

Step 2) Divide the total mass of chlorine by the total mass of the compound.

3(35.453) = 106.359

106.359/119.378 = 0.8909430548.

Step 3) Now multiply by 100 to get the percentage.

0.8909430548*100 = 89.09430548%

Step 4) Estimate and submit your answer

89.09430548% estimates to 89%

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How many grams of hydrogen reacts with 32 g of oxygen to produce 34 g of hydrogen peroxide
nordsb [41]

Answer:

2 grams.

Explanation:

H2 + O2 --->  H2O2

Using molar masses:

2*1 g hydrogen   reacts with 2*16  g oxygen.

so 2g H2 reacts with 32 g O2.

8 0
3 years ago
How many grams of lead(II) sulfate (303 g/mol) are needed to react with sodium chromate (162 g/mol) in order to produce 0.162 kg
Afina-wow [57]

Answer : The mass of PbSO_4 needed are, 1.515 grams.

Explanation :

First we have to calculate the mole of PbCrO_4.

\text{Moles of }PbCrO_4=\frac{\text{Mass of }PbCrO_4}{\text{Molar mass of }PbCrO_4}=\frac{0.162g}{323g/mole}=0.005mole

Now we have to calculate the moles of PbSO_4.

The balanced chemical reaction will be,

PbSO_4+Na_2CrO_4\rightarrow PbCrO_4+Na_2SO_4[tex]From the balanced chemical reaction, we conclude thatAs, 1 mole of [tex]PbCrO_4 produced from 1 mole of PbSO_4

So, 0.005 mole of PbCrO_4 produced from 0.005 mole of PbSO_4

Now we have to calculate the mass of PbSO_4

\text{Mass of }PbSO_4=\text{Moles of }PbSO_4\times \text{Molar mass of }PbSO_4

\text{Mass of }PbSO_4=0.005mole\times 303g/mole=1.515g

Therefore, the mass of PbSO_4 needed are, 1.515 grams.

6 0
3 years ago
A teardrop-shaped hill that points the direction a glacier has flowed is a:
mote1985 [20]
The answer is A Drumlin

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Naphthalene is insoluble in NaOH.
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