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kolezko [41]
3 years ago
11

Calculate the percent composition of chlorine in methyl trichloride, CHCl3.

Chemistry
1 answer:
vovikov84 [41]3 years ago
5 0

Answer:

Chlorine --> 89%

Explanation:

Step 1) Add each element's amu up to get the total mass of the compound.

12.011+1.008+3(35.453) = 119.378.

Step 2) Divide the total mass of chlorine by the total mass of the compound.

3(35.453) = 106.359

106.359/119.378 = 0.8909430548.

Step 3) Now multiply by 100 to get the percentage.

0.8909430548*100 = 89.09430548%

Step 4) Estimate and submit your answer

89.09430548% estimates to 89%

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12.23 g of ammonia (NH3) are dissolved in enough water to make 560.0 mL of solution. How many moles of NH3 are added to the wate
Karolina [17]

Answer:

0.719 moles of NH₃

Explanation:

Molar mass of ammonia 17 g/mol

Mass of amonia = 12.23 g

Mass / Molar mass = Moles

12.23 g / 17 g/mol = 0.719 moles

4 0
3 years ago
What is true of a molecule?
nalin [4]

Answer:

All molecules of a compound have one type of atom.FLASE, compounds aren't one type, there compounds

Each molecule of a compound has different properties false

All molecules of a compound have the same properties true

Each atom of a molecule is the same FALSE

Explanation:

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8 0
3 years ago
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What is the difference between a mixture and compound?
rewona [7]

Compound: a thing that is composed of two or more separate elements, basically it is a mixture

Mixture: a substance made by mixing other substances together

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4 0
3 years ago
Just as heat can denature enzymes, so can a change in the pH. Enzymes that normally work in an acidic environment in the body ca
nikitadnepr [17]

Answer:

It will create an alkaline environment and can lead to denaturation of acidic enzymes.

Explanation:

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5 0
3 years ago
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Calculate the percent by mass of potassium nitrate in a solution made from 45.0 g kno3 and 295 ml of water. The density of water
Tanzania [10]

Answer:  the percent by mass of potassium nitrate is 13.3%

Explanation:

<u>1) Data:</u>

  • Mass of solute, m₁ = 45.0 g
  • Volume of solvent, V₂ = 295 ml
  • density of water, d₂ = 0.997 g/ml

<u>2) Formulae</u>:

  • Percent by mass, % = (mass of solute / mass of solution) × 100

  • Density, d = mass / volume

<u>3) Solution</u>:

  • d = mass / volume ⇒ m₂ = d₂ × V₂ = 0.997 g/ml × 295 ml = 294. g
  • mass of solution = m₁ + m₂ = 45.0g + 294. g = 339. g
  • % = (45.0 g / 339. g) × 100 = 13.3 %
  • The answer has to be reported with 3 significant figures.
6 0
4 years ago
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