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poizon [28]
3 years ago
5

What are the Big Five Personality Factors?

Physics
2 answers:
Zarrin [17]3 years ago
8 0

Answer:

O-penness.

C-onscientiousness.

E-xtraversion.

A-greeableness.

N-euroticism.

(ocean)

hope this helps

Veronika [31]3 years ago
5 0
Friends and skckfkfkrmgklvkfkkaksk
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(i) (a) what is the force per meter of length on a straight wire carrying a 9.75 a current when perpendicular to a 0.81 t unifor
Andrew [12]
The force generated by a magnetic field B perpendicular to a wire carrying a current I is
F=ILB
where L is the length of the wire.

If we divide both sides for L, we get
\frac{F}{L}=IB
where the ratio on the left is the force per meter of length, which is exactly what we want to find. So:
\frac{F}{L}=IB=(9.75 A)(0.81 A)=7.90 N/m
5 0
4 years ago
Plzzzz help me and I will mark u the brainiest
Veronika [31]
A.) 3,800
* Add 1800+2000 because they are both going forward, and you are look for the total amount of forward force. Hope this helped good luck!!!
6 0
3 years ago
If you took a white piece of plastic to a depth of 180 m, what color would it appear?.
SashulF [63]

Answer:

It would appear blue

Explanation:

3 0
2 years ago
HELPPPPPPP !!!!!! PLS A 0.050 kg Truck moving right at 0.20 m/s collides with a toy race car weighing 0.015 kg initially at rest
sergejj [24]

Answer:

v_f=0.15\:\mathrm{m/s}

Explanation:

From the Law of Conservation of Momentum, we can write the following equation:

m_1v_1+m_2v_2=m_fv_f

Because the toy car was initially at rest, m_2v_2=0.

Therefore, we can plug in given values and solve for v_f:

m_1v_1=m_fv_f,\\0.050\cdot 0.20 = (0.050+0.015)v_f,\\v_f=\fbox{$0.15\:\mathrm{m/s}$} (two significant figures).

6 0
3 years ago
A railroad car with a mass of 1.94 ✕ 104 kg moving at 3.28 m/s joins with two railroad cars already joined together, each with t
kap26 [50]
The total cost is going to be 536 kg
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4 years ago
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