My guess would be 101 kPa but I'm not 100% sure, sorry.
All the angles of reflection are +3° off, so systematic error.
The device used to measure the angle might be miscalibrated or have incorrect markings.
Black and Whites were hungry and thirsty
<h3><u>Answer;</u></h3>
A.75°C
<h3><u>Explanation</u>;</h3>
Let the change in temp of cold water be x degrees,
while that of hot water be 100 - x degrees.
Heat exchange = mcΔt
Ice
Δt = x
m = 0.50 kg
c = 4.18 kJ/kg*°C
Hot water
Δt = 100 - x
m = 1.5 kg
c = 4.18
But;
Heat lost = heat gained
0.50 * c * x = 1.5 * c * (100 - x)
0.50 *x = 1.5*(100 - x)
0.5x = 150 - 1.5x
0.5x + 1.5x = 150 - 1.5x + 1.5x
2x = 150
x = <u>75° C</u>
Hence; the equilbrium temperature will be 75° C
To solve the exercise, the key concept to be addressed is the Mass Center.
The center of mass of an object is measured as,


Our values are given by,







Replacing the values in our previous equation we have,






Therefore the mass of the meter stick is 7.928g