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romanna [79]
2 years ago
10

A young man and woman are sitting on opposite sides of a park bench (1m). If the young man has a mass of 70kg and the woman has

a mass of 60kg, what is the force between them?
Physics
1 answer:
ZanzabumX [31]2 years ago
6 0

Answer:

130N

Explanation:

F<em>=</em><em>(</em><em>M1+</em><em>M</em><em>2</em><em>)</em><em>V</em>

<em>F=</em><em> </em><em>(</em><em>7</em><em>0</em><em>+</em><em>6</em><em>0</em><em>)</em><em>*</em><em>1</em>

<em>F=</em><em>1</em><em>3</em><em>0</em><em>*</em><em>1</em>

<em>F=</em><em>1</em><em>3</em><em>0</em><em>N</em><em>/</em><em>/</em>

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A war wolf is a device used during the middle ages to assault fortifications with large rocks. A simple trebuchet is constructed
Katarina [22]

Answer:v=41.23 m/s

Explanation:

Given

mass of heavy object m_1=52 kg

distance of m_1 from the axle r_1=14 cm

mass of rock m_2=123 gm

Length of rod =4.1 m

distance of m_2 from axle r_2=4.1-0.14=3.96 m

Net torque acting is

T_{net}=m_1gr_1-m_2gr_2

T_{net}=52\times 0.14\times g-0.123\times 3.96\times g

T_{net}=6.793\times 9.8

T_{net}=66.57 N-m

Work done by T_{net} is converted to rock kinetic Energy

thus

T_{net}\times \theta =\frac{mv^2}{2}

Where \theta =angle\ turned =\frac{\pi }{2}

v= velocity\ at\ launch

66.57\times \frac{\pi }{2}=\frac{0.123\times v^2}{2}

v^2=66.57\times \pi

v=\sqrt{1700.511}

v=41.23 m/s

3 0
3 years ago
A sonar emits a sound signal of frequency 40000Hz, towards the bottom of the sea.
kap26 [50]

Answer:

0.000025s

Explanation:

Period it’s. : T(s)= 1/f(Hz)=1/40000Hz=0.000025s

8 0
2 years ago
f the magnitude of the acceleration of a propeller blade's tip exceeds a certain value amaxamax, the blade tip will fracture. If
Luden [163]

Answer:

The angular velocity is   w= \sqrt[4]{\frac{a_{max}^2}{r^2}  - \alpha ^2}      

Explanation:

Generally the acceleration experienced by the propeller blade's is broken down into

          The Radial acceleration which is mathematically represented as

                              a_r = \frac{v^2}{r}  = w^2r

And the Tangential  acceleration which is mathematically represented as

                                a_r = \alpha r

  The net acceleration is evaluated as

                      a = \sqrt{a_r^2 + a_t^2}

       

Now since angular speed varies directly with angular acceleration so when acceleration is maximum the angular velocity is maximum also and this point if the propeller blade's tip exceeds it the blade would fracture

                 

So at maximum angular acceleration we a have

             a_{max} = \sqrt{a_r^2 + a_t^2}

                     a_{max}^2 = a_r^2 + a_t^2

                    a_{max}^2 = (w^2r)^2 + (\alpha r)^2

                 a_{max}^2 =  r^2 w^4 + r^2 \alpha ^2

                  a_{max}^2 = r^2 (w^4 + \alpha^2 )

                w^4 +\alpha ^2 = \frac{a_{max}^2}{r^2}

                         w^4 = \frac{a_{max}^2}{r^2}  - \alpha ^2

                         w= \sqrt[4]{\frac{a_{max}^2}{r^2}  - \alpha ^2}        

                     

3 0
3 years ago
The mass of a lift is 600kg.the. The maximum tensile force that the cable supporting the lift can withstand is 7kN. Calculate th
Oksi-84 [34.3K]
Force is the product of mass and acceleration .
The question is ask to find acceleration.
But acceleration is the ratio of the force and the mass.
where 600kg is the mass and 7kN is the force
NB: kilo is 1000
now we have to multiply 7N by 1000
by doing so you will have 7000N
which is the force.
Now to find the acceleration: force/ mass
which is 7000/600
therefore the maximum acceleration is 11.667


5 0
3 years ago
Calculate the pressure exerted on the floor when an elephant who weighs 6000 N stands on one foot which has an area of 20 m2
kondor19780726 [428]

Answer:

300 Pascal

Explanation:

Given

weight or force (F) = 6000 N

area (A) = 20 m²

pressure (p) = ?

we know

the force acting normally per unit area is pressure. So

P = F / A

= 6000 / 20

= 300 Pascal

Hope it will help :)

3 0
3 years ago
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