Answer: The electronic configuration of iron is: Ar3d64s2. the two electrons in the 4s orbital are paired, and two of the electrons in the 3d orbitals are paired leaving four unpaired electrons.
Explanation:
Answer:
0.99 kg O₂
1.9 kg SO₂
Explanation:
Let's consider the reaction between sulfur and oxygen to form sulfur dioxide.
S + O₂ → SO₂
The mass ratio of S to O₂ is 32.07:32.00. The mass of oxygen required to react with 1 kg of sulfur is:
1 kg S × (32.00 kg O₂/32.07 kg S) = 0.998 kg O₂
The mass ratio of S to SO₂ is 32.07:64.07. The mass of sulfur dioxide formed when 1 kg of sulfur is burned is:
1 kg S × (64.07 kg SO₂/32.07 kg S) = 1.99 kg SO₂
Cu(s) + 2 AgNO3 = Cu(NO3)2 + 2 Ag 63.5 g Cu ---------------- 2 x 169.87 g AgNO3 ( mass Cu ?) -------------- 4.00 g AgNO3 mass Cu = 4.00 x 63.5 / 2 x 169.87 mass Cu = 254 / 339.74 = 0.747 g of Cu
Hope this helps
I believe it lies in the 3rd Quadrent