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Leni [432]
3 years ago
7

1. How many moles of LiBr are present in 100 mL of 1.25M LIBr solution?

Chemistry
1 answer:
Svet_ta [14]3 years ago
7 0

Answer:

https://www.webassign.net/question_assets/wertzcams3/appendix.pdf

You might be interested in
How do elements on the right side of the periodic table differ from elements on the left side of the table?
lozanna [386]

The answer is c.


Elements on the left side of the table are metals, such as sodium, lithium, potassium, etc.


Elements on the right side are non metals, such as Chlorine, Fluorine, Bromine, etc.

4 0
3 years ago
A scientist has 0.12 miles of a gas at a pressure of 4.06 kPa and a volume of 14 liters in an enclosed container. What is the te
natka813 [3]

Answer:

56972.17K

Explanation:

P = 4.06kPa = 4.06×10³Pa

V = 14L

n = 0.12 moles

R = 8.314J/Mol.K

T = ?

We need ideal gas equation to solve this question

From ideal gas equation,

PV = nRT

P = pressure of the ideal gas

V = volume the gas occupies

n = number of moles

R = ideal gas constant

T = temperature of the gas

PV = nRT

T = PV / nR

T = (4.06×10³ × 14) / (0.12 × 8.314)

T = 56840 / 0.99768

T = 56972.17K

Note : we have a large number for temperature because we converted the value of pressure from kPa to Pa

7 0
3 years ago
(6 points) Calculate the maximum number of moles and grams of H2S that can form when 158 g of aluminum sulfide reacts with 131 g
Schach [20]

Answer:107.1 g, 124.1 g

Explanation:

The equation of the reaction is;

Al2S3(s) + 6H20(l) ----> 2Al(OH)3(s) + 3H2S(g)

Hence;

For Al2S3

Number of moles= reacting mass/molar mass

Number of moles = 158g/150gmol-1 =1.05 moles

If 1 mole of Al2S3 yields 3 moles of H2S

1.05 moles of Al2S will yield

1.05 × 3/1 = 3.15 moles

Mass of H2S = 3.15moles × 34 gmol-1 = 107.1 g

For water

Number of moles of water = 131g/18gmol-1= 7.3 moles

6 moles of water yields 3 moles of H2S

7.3 moles of water will yield 7.3 × 3/6 = 3.65 moles of H2S

3.65 moles × 34 gmol-1 =124.1 g

5 0
3 years ago
How many litres (L) of oxygen at STP can be obtained from 110 g of potassium chlorate? [R=0.0821 L.atm/K.mol]
lisabon 2012 [21]
Balance the equation first:

2 KClO3 (s) ---> 2 KCl (s) + 3 O2 (g)

Moles of KClO3 =  110 / 122.5 = 0.89

Following the balanced chemical equation:
We can say moles of O2 produce =  \frac{3}{2} x moles of KClO3

So, O2 = (3 / 2) x  0.89

= 1.34 moles

So, Volume at STP = nRT / P

T = <span>273.15 K
P = 1 atm

So, V = (1.34 x 0.0821 x 273.15) / 1  =  30.2 L</span>
3 0
3 years ago
QUESTION 7
Temka [501]

The student's test average is : 0.92

Total score obtained = 369

Number of tests = 4

Since Each test is exactly 100 points ;

The total score obtainable is (100 × 4) = 400

Average = score obtained / total score obtainable

Average = 369 / 400

Average = 0.9225

Average = 0.92

Learn more : brainly.com/question/9416487?referrer=searchResults

5 0
3 years ago
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