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rewona [7]
3 years ago
10

Hooke's law. The distance d when a spring is stretched by a hanging objective varies directly as the weight w of the object. If

the distance is 38 cm when the weight is 3 kg, what is the distance when the weight is 7 kg? ...?
Physics
1 answer:
Fofino [41]3 years ago
7 0
<span>Hooke's law is F=-kx, which means the elastic force contained by the spring is a product of the distance it stretches and its spring constant, but the direction of the force is opposite that of the displacement. We calculate as follows:

</span><span>(3 kg)(9.8 m/s^2) = -k(-0.38 m)
</span>k =<span> 77.4

</span><span>Then use k to find the new displacement, again using Hooke's law:
(7 kg)(9.8 m/s^2) = -(77.4)x
x = -0.89 m</span>
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Here,

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range of different spectrum

UV ----0.01-0.4

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fractions

for UV = 0.125  

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for infrared = 1 -0.491 = 0.509  

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