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REY [17]
3 years ago
9

Forces of 2 newtons and 3 newtons are acting on an object as shown in the drawing below. Calculate the resultant force in newton

s and determine its direction.
Vectors

Select one:
a. 1 N upward
b. 5 N upward
c. 1 N downward
d. 5 N downward​

Physics
1 answer:
Kipish [7]3 years ago
5 0

Answer:

Hey mate

Your answer will be <u>5 N</u><u> </u><u>Upwards</u><u>.</u><u> </u>

I will explain this to you.

In the attachment we can see that there are two forces acting on the object from the same side. And we know that when force acts from the same direction. Then the total force

=> sum of all the forces in that particular direction.

I hope you got it :)

TheSarcasmic

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A stone is thrown vertically upwards with an initial velocity of 20m/sec. Find the maximum height ot reaches and the time taken
MAXImum [283]

Answer:

The height reached is 20m, The time taken to reach 20m is 2 seconds

Explanation:

Observing the equations of motion we can see that the following equation will be most helpful for this question.

v^{2} = u^{2} + 2as

We are given initial velocity, u

We know that the stone will stop at its maximum height, so final velocity, v

Acceleration, a

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0^{2} = 20^{2} + 2(10)s

Rearrange for s

0^{2} -20^{2} =20s

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\frac{-400}{20} =s

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Use a different equation to find the time taken

s = vt - \frac{1}{2} at^{2}

Substitute in the values we have

-20=(0)t - \frac{1}{2} (10)t^{2}

Rearrange for t

-20 =0 -5 t^{2}

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4 = t^{2}

t = 2s

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4 0
3 years ago
If a 20 kg green fish swimming at 2 m/s swallows a 1 kg orange fish at rest, in what direction, and how fast
krok68 [10]

Answer: 1.9 m/s

Explanation:

The question should be:

If a 20 kg green fish swimming at 2 m/s swallows a 1 kg orange fish at rest, in what direction, and how fast  will the green fish swim after eating the orange fish?

Ok, here we have conservation of momentum.

At the beginning, the total momentum is equal to the sum between the momentum of the green fish and the momentum of the orange fish.

Where the momentum is written as:

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The momentum of the orange fish is:

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For conservation of momentum, the initial momentum is equal to the final momentum, then:

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40 kg*m/s = 21kg*V

(40/21) m/s = 1.9 m/s = V

The fish's final velocity is 1.9 m/s

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