We can use the ideal gas law equation to find the number of moles in the gas
PV = nRTwhere P - pressure - 1.2 atm x 101 325 Pa/atm = 121 590 Pa
V - volume - 3.94 x 10⁻³ m³
n - number of moles
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature - 15 °C + 273 = 288 K
substituting the values in the equation
121 590 Pa x 3.94 x 10⁻³ m³ = n x 8.314 Jmol⁻¹K⁻¹ x 288 K
n = 0.200 mol
molar mass of gas is = mass / number of moles
molar mass = 12.8 g / 0.200 mol = 64 g/mol
molar mass of gas is 64 g/mol
Answer:
Which ever item has more water inside of it
Explanation:
A Neutralisation reaction, the alkali is neutralizing the acid.
Answer:
1121.08 millilitres of 0.223 M 
solution contains 0.250 moles of .
Explanation:
The formula for molarity of a solution:
Molarity = 0.223 M
n = 0.250 moles
Therefore, 1121.08 millilitres of 0.223 M solution contains 0.250 moles of .
Answer:
TRIAL 1:
For “Event 0”, put 100 pennies in a large plastic or cardboard container.
For “Event 1”, shake the container 10 times. This represents a radioactive decay event.
Open the lid. Remove all the pennies that have turned up tails. Record the number removed.
Record the number of radioactive pennies remaining.
For “Event 2”, replace the lid and repeat steps 2 to 4.
Repeat for Events 3, 4, 5 … until no pennies remain in the container.
TRIAL 2:
Repeat Trial 1, starting anew with 100 pennies.
Calculate for each event the average number of radioactive pennies that remain after shaking.
Plot the average number of radioactive pennies after shaking vs. the Event Number. Start with Event 0, when all the pennies are radioactive. Estimate the half-life — the number of events required for half of the pennies to decay.
Explanation:
