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3 years ago

Will the scientific method be different 100 years from now ? Why or why not?

2 answers:

5 0

NO, it should not be the process is still the same . the only factors about it that should change is the experiment itself.:)

kicyunya [14]3 years ago

4 0

It might if there is another necessary safety of intelligence requirement allocated by the government

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is it possible for a balloon with an initial pressure of 200.0 kpa to naturally expand to four times its initial volume when the

lorasvet [3.4K]

You can find the ratio that it can expand with the atmospheric pressure.

200.0/101.3= 1.97 ≈ 2, this means that the balloon could expand twice its initial volume. So, it is not possible for the balloon to expand to 4 since the maximum is 2.

5 0

3 years ago

Read 2 more answers

Carbon tetrachloride can be produced by the following reaction: Suppose 1.20 mol of and 3.60 mol of were placed in a 1.00-L flas

hjlf

The given question is incomplete. The complete question is :

Carbon tetrachloride can be produced by the following reaction:

$CS_2(g)+3Cl_2(g)\rightleftharpoons S_2Cl_2(g)+CCl_4(g)$

Suppose 1.20 mol $CS_2(g)$ of and 3.60 mol of $Cl_2(g)$ were placed in a 1.00-L flask at an unknown temperature. After equilibrium has been achieved, the mixture contains 0.72 mol of $CCl_4$ . Calculate equilibrium constant at the unknown temperature.

Answer: The equilibrium constant at unknown temperature is 0.36

Explanation:

Moles of $CS_2$ = 1.20 mole

Moles of $Cl_2$ = 3.60 mole

Volume of solution = 1.00 L

Initial concentration of $CS_2$ = $\frac{moles}{volume}=\frac{1.20mol}{1L}=1.20M$

Initial concentration of $Cl_2$ = $\frac{moles}{volume}=\frac{3.60mol}{1L}=3.60M$

The given balanced equilibrium reaction is,

$CS_2(g)+3Cl_2(g)\rightleftharpoons S_2Cl_2(g)+CCl_4(g)$

Initial conc. 1.20 M 3.60 M 0 0

At eqm. conc. (1.20-x) M (3.60-3x) M (x) M (x) M

The expression for equilibrium constant for this reaction will be,

$K_c=\frac{[S_2Cl_2]\times [CCl_4]}{[Cl_2]^3[CS_2]}$

Now put all the given values in this expression, we get :

$K_c=\frac{(x)\times (x)}{(3.60-3x)^3\times (1.20-x)}$

Given :Equilibrium concentration of $CCl_4$ , x = $\frac{moles}{volume}=\frac{0.72mol}{1L}=0.72M$

$K_c=\frac{(0.72)\times (0.72)}{(3.60-3\times 0.72)^3\times (1.20-0.72)}$

$K_c=0.36$

Thus equilibrium constant at unknown temperature is 0.36

4 0

2 years ago

A chemist needs 1.36 mol of strontium bromide, SrBr2, for a reaction. What mass of strontium chloride should the chemist use?

yaroslaw [1]

Mass SrBr2 = 247.42 g/mol x 1.36 mol
<span>= 336 g</span>

5 0

3 years ago

Read 2 more answers

How many protons, neutrons, and electrons are in Uranium-232? How many protons, neutrons, and electrons are in Uranium-232?

QveST [7]

Protons/Electrons: 92

Neutrons: 140

***REMEMBER: There is always the same amount of protons and electrons. :)

7 0

3 years ago

7. Write a formula for each of the following:

sergeinik [125]

Answer : The formula for each of the following is:

(a) $C_{22}H_{46}$

(b) $C_{17}H_{34}$

(c) $C_{13}H_{24}$

Explanation :

Alkanes are hydrocarbon in which the carbon atoms are connected with single covalent bonds.

The general formula of alkanes is $C_n H_{2n+2}$ where n is the number of the carbon atoms present in a molecule of alkane.

Alkenes are hydrocarbon in which the carbon atoms are connected with double covalent bonds.

The general formula of alkenes is $C_n H_{2n}$ where n is the number of the carbon atoms present in a molecule of alkene.

Alkynes are hydrocarbon in which the carbon atoms are connected with triple covalent bonds.

The general formula of alkynes is $C_n H_{2n-2}$ where n is the number of the carbon atoms present in a molecule of alkyne.

(a) An alkane with 22 carbon atoms

Putting n = 22 in the general formula of alkane, we get the formula of alkane as, $C_{22}H_{2(22)+2}$ or $C_{22}H_{46}$

(b) An alkene with 17 carbon atoms

Putting n = 17 in the general formula of alkene, we get the formula of alkene as, $C_{17}H_{2(17)}$ or $C_{17}H_{34}$

(c) An alkyne with 13 carbon atoms

Putting n = 13 in the general formula of alkyne, we get the formula of alkyne as, $C_{13}H_{2(13)-2}$ or $C_{13}H_{24}$

3 0

3 years ago

Read 2 more answers