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Maksim231197 [3]
3 years ago
11

Will the scientific method be different 100 years from now ? Why or why not?

Chemistry
2 answers:
sveta [45]3 years ago
5 0
NO, it should not be the process is still the same . the only factors about it that should change is the experiment itself.:)
kicyunya [14]3 years ago
4 0
It might if there is another necessary safety of intelligence requirement allocated by the government
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Please tell me the answer I will mark you brainliest
Shkiper50 [21]

Answer:

3

Explanation:

third answer might be right

8 0
2 years ago
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Determine the concentration of an HBr solution if a 45.00 mL aliquot of the solution yields 0.5555 g AgBr when added to a soluti
amid [387]
Molecular weight of AgBr = 187.7
moles of Ag = \frac{0.5555}{187.7} = 2.96 x 10^{-3}
moles of Br = moles of Ag = 2.96 x 10⁻³ mol
concentration of HBr (Molarity) = conc. of Br (strong acid) = \frac{2.96 x 10^{-3} }{45 x 10^{-3} } = 0.0658 mol/l
6 0
2 years ago
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Identify both the cellular structure that assembles these proteins and the kinds of molecules that are used as the building bloc
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7 0
3 years ago
Positive Deviation from Raoult's Law occurs when the vapour pressure of component is greater than what is expected in Raoult's L
8090 [49]

Answer:

All of the above.

Explanation:

In positive deviation from Raoult's  Law occur when the vapour pressure of components is greater than what is expected value in Raoult's law.

When a solution is non ideal then it shows positive or negative deviation.

Let two solutions A and B to form non- ideal solutions.let the vapour pressure  of component A is P_A and vapour pressure of component B is P_B.

P^0_A= Vapour pressure of component A in pure form

P^0_B= Vapour pressure of component B in pure form

x_A=Mole fraction of component A

x_B==Mole fraction of component B

The interaction between A- B is less than the interaction A- A and B-B interaction.Therefore, the escaping tendency of liquid molecules in mixture is greater than the escaping tendency in pure form.Hence, the vapour pressure of a mixture is greater than the initial value of vapour pressure.

P_A >P^0_A\cdot x_A,P_B>P^0_B\cdot x_B

Therefore, P_A+P_B >P^0_A\cdot x_A+P^0_B \cdot x_B

Therefore, the enthalpy of mixing is greater than zero and change in volume is greater than zero.

Hence, option a,b,c and d are true.

6 0
3 years ago
You used a calorimeter in the heat transfer lab. Explain how the calorimeter works, and how to calculate the heat given off or a
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A calorimeter contains reactants and a substance to absorb the heat absorbed. The initial temperature (before the reaction) of the heat absorbent is measured and then the final temperature (after the reaction) is also measured. The absorbent's specific heat capacity and mass are also known. Given all of this data, the equation:
Q = mcΔT 
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