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Lostsunrise [7]
3 years ago
15

A chemist needs 0.550 mol selenium for a reaction. What mass of selenium should a chemist use?

Chemistry
1 answer:
-BARSIC- [3]3 years ago
4 0

Answer:

The chemist would require to use 43.43 grams.

Explanation:

In order to solve this problem we need to know<u> how much do 0.550 moles of selenium weigh</u>. To do that we use selenium's<em> molar mass </em>and multiply it by the given number of moles:

  • 0.550 mol * 78.96 g/mol = 43.43 g

The chemist would require to use 43.43 grams.

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What force causes water to run down a mountain
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3 years ago
Which of the following solutions is a good buffer system?A solution that is 0.10 M HCN and 0.10 M NaClA solution that is 0.10 M
patriot [66]

Answer:

A solution that is 0.10 M HCN and 0.10 M LiCN

Explanation:

  • A good buffer system contains a weak acid and its salt or a weak base and its salt.
  • In this case; A solution that is 0.10 M HCN and 0.10 M LiCN, would make a good buffer system.
  • HCN is a weak acid, while LiCN is a salt of the weak acid, that is, CN- conjugate of the acid.
8 0
3 years ago
A. 207 kJ<br> B. 4730 kJ<br> O C. 9460 kJ<br> O D. 414 kJ
slavikrds [6]

Answer:

C = 9460 Kj

Explanation:

Given data:

Mass of copper = 2kg

Latent heat of vaporization = 4730 Kj/Kg

Energy required to vaporize 2kg copper = ?

Solution:

Equation

Q= mLvap

by putting values,

Q= 2kg ×  4730 Kj/Kg

Q = 9460 Kj

3 0
3 years ago
What is the percent composition of nitrogen in a 2.57 g sample of Al(NO3)3?
Lisa [10]

Answer:

19.8% of Nitrogen

Explanation:

In the Al(NO₃)₃ there are:

1 atom of Al

3 atoms of N

And 9 atoms of O

The molar mass of Al(NO₃)₃ is:

1 Al * (26.98g/mol) = 26.98g/mol

3 N * (14g/mol) = 42g/mol

9 O * (16g/mol) = 144g/mol

26.98 + 42 + 144 = 212.98g/mol

We can do a conversion using these molar masses to find the mass of nitrogen is the sample, that is:

2.57g * (42g/mol / 212.98g/mol) =

0.51g N

Percent composition of nitrogen is:

0.51g N / 2.57g * 100

= 19.8% of Nitrogen

6 0
2 years ago
5. How many grams of CuCl2 are required to make 75 mL of a 0.20M solution?
Effectus [21]
35.8 cuc12 jk jk ok jk
5 0
2 years ago
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