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zzz [600]
3 years ago
13

A spring is used to launch a coffee mug. The 20cm long spring can be compressed by a maximum of 8cm. The mug has a mass of 500 g

. What kind of spring do you need to launch the mug at least 2 stories high (5 m) - as measured from the relaxed spring position - using the maximum compression?
Physics
1 answer:
Otrada [13]3 years ago
8 0

Answer:

7664.06249 N/m

Explanation:

m = Mass of mug = 0.5 kg

x = Compression of spring = 0.08 m

h = Height of fall = 5 m

g = Acceleration due to gravity = 9.81 m/s²

The kinetic energy of the spring and potential energy of the fall are conserved

\frac{1}{2}kx^2=mgh\\\Rightarrow k=\frac{2mgh}{x^2}\\\Rightarrow k=\frac{2\times 0.5\times 9.81\times 5}{0.08^2}\\\Rightarrow k=7664.06249\ N/m

The spring constant of the spring is 7664.06249 N/m

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an NHL hockey player (m=90 kg) stands motionless on the ice . the 10 kg stanley cup is thrown to the player at 4m/s. after he ca
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4 0
3 years ago
The tallest building in the world, according to some architectural standards, is the Taipei 101 in Taiwan, at a height of 1671 f
Andrej [43]

Answer:

35.14°C

Explanation:

The equation for linear thermal expansion is \Delta L = \alpha L_0\Delta T, which means that a bar of length L_0 with a thermal expansion coefficient \alpha under a temperature variation \Delta T will experiment a length variation \Delta L.

We have then \Delta L = 0.481 foot, L_0 = 1671 feet and \alpha = 0.000013 per centigrade degree (this is just the linear thermal expansion of steel that you must find in a table), which means from the equation for linear thermal expansion that we have a \Delta T =\frac{\Delta L }{\alpha L_0} = 22.14°. As said before, these degrees are centigrades (Celsius or Kelvin, it does not matter since it is only a variation), and the foot units cancel on the equation, showing no further conversion was needed.

Since our temperature on a cool spring day was 13.0°C, our new temperature must be T_f=T_0+\Delta T = 35.14°C

3 0
4 years ago
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