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pav-90 [236]
3 years ago
8

What is the net electric force on the charge located at the lower right-hand corner of the triangle.

Physics
1 answer:
Inga [223]3 years ago
6 0

Answer:

\sqrt{3}\frac{kq^{2}}{a^{2} }

Explanation:

none sadly

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The minimum energy required for an effective collision is called
kifflom [539]

Answer:

Activation Energy

Explanation:

Effective collisions are those that result in a chemical reaction. In order to produce an effective collision, reactant particles must possess some minimum amount of energy. This energy, used to initiate the reaction, is called the activation energy.

6 0
4 years ago
1. How does RNA differ from DNA?
9966 [12]
The answer is c) RNA contains uracil and ribose.
7 0
3 years ago
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The junction rule describes the conservation of which quantity? Note that this rule applies only to circuits that are in a stead
Fed [463]

Answer:

a) Current.

Explanation:

The "junction rule" (Kirchhoff's first law) says that the value of the electric current entering any point in the circuit must be the same as the one leaving it. This comes as a consequence of the conservation of charge, the electric charge that comes in must come out (when speaking about currents, per unit time).

3 0
3 years ago
A ray of light strikes the midpoint of one face of an equiangular crown glass prism (n=1.52) at an angle of incidence of 30.0.
NikAS [45]

Answer:

Angle of reflection  at plane surface of prism = 30°

Explanation:

Angle of reflection = angle of incidence at any surface plane or curved .

Here angle of incidence at plane surface of prism = 30°

Angle of reflection  at plane surface of prism = 30°

If i be the angle of incidence and r be angle of refraction

sin i / sin r = refractive index

= 1.52

sin r = sin i / 1.52

=  sin 30 / 1.52

= .5 / 1.52

= .3289

r = 19.2 °

6 0
3 years ago
In the attached position versus time graph what is the magnitude of average velocity for the entire 19 seconds of the motion. An
evablogger [386]

According to the plot, the positions at time <em>t</em> = 0 s and <em>t</em> = 19 s are -1 m and -2 m, respectively. So the average velocity for the 19-s interval is

v_{\rm ave} = \dfrac{-2\,\mathrm m - (-1\,\mathrm m)}{19\,\mathrm s} = -\dfrac1{19}\dfrac{\rm m}{\rm s}\approx \boxed{-0.05\dfrac{\rm m}{\rm s}}

8 0
3 years ago
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