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4 years ago

Please answer this question

Physics

2 answers:

Otrada [13]4 years ago

5 0

Number 3 is b. petrologist
Number 4 is a.metamorphic

Ilya [14]4 years ago

5 0

1.d
3.b
4.a
5.f
hope this helped

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What equation describes conservation of charge?

Phantasy [73]

Answer:

The equation which describes conservation of charge is $Q_{initial} - Q_{final } = 0$

Explanation:

The law of conservation charge states that for an isolated system that sum of initial charges is equal to sum of final charges, that is the total charge is conserved.

let the sum of initial charges = $Q_{initial}$

let the sum of the final charges = $Q_{final}$

$Q_{initial } = Q_{final}\\\\Q_{initial } - Q_{final} = 0$

Therefore, the equation which describes conservation of charge is $Q_{initial} - Q_{final } = 0$

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3 years ago

Distance and direction of an object's change in position from a starting point are:

blsea [12.9K]

Answer:

An object changes position if it moves relative to a reference point. The change in position is determined by the distance and direction of an object's change in position from the starting point (displacement). Direction • Direction is the line, or path along which something is moving, pointing, or aiming.

Explanation:

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3 years ago

Read 2 more answers

Two charged objects separated by some distance attract each other. If the charges on both objects are doubled with no change in

Serggg [28]

Answer:

(a) The force between them quadruples

Explanation:

According to coulomb's law, initial force between the two charged objects is given as;

$F_1=\frac{Kq_1q_2}{r^2}$

where;

k is coulomb's constant

q₁ is the charge on the first object

q₂ is the charge on the second object

r is the distance between the two objects

When the charges on both objects are doubled, then;

q₁ = 2q₁

q₂ = 2q₂

Force between the two charged objects will become

$F_2 = \frac{K2q_12q_2}{r^2} = \frac{4Kq_1q_2}{r^2} = 4(\frac{Kq_1q_2}{r^2}) = 4F_1$

Therefore, the force between them quadruples

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3 years ago

Professor Frank Nabarro insists that all senior physics majors take his notorious physics aptitude test. The test is so tough th

yulyashka [42]

Answer:

0.5504

Explanation:

We can use Bay's theorem to solve this question

P( No physics career/fail) = P(No Physics career and fail)/P(Fail)

= P( Fail/ No physics career)×P( no physics career)/P( fail)

= $\frac{0.3\times1}{(0.7\times0.35)+(0.3\times1)}$

=0.5504

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3 years ago

Dolphins emit clicks of sound for communication and echolocation. A marine biologist is monitoring a dolphin swimming in seawate

LenKa [72]

Answer:

12.64968 Hz

Explanation:

v = Velocity of sound in seawater = 1522 m/s

u = Velocity of dolphin = 7.2 m/s

f' = Actual frequency = 2674 Hz

From Doppler effect we get the relation

$f=f'\frac{v-u}{v}\\\Rightarrow f=2674\frac{1522-7.2}{1522}\\\Rightarrow f=2661.35032\ Hz$

The frequency that will be received is 2661.35032 Hz

The difference in the frequency will be

$2674-2661.35032=12.64968\ Hz$

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4 years ago