Ask question

Ask question

All categories

4 years ago

9

Please answer this question

2 answers:

Otrada [13]4 years ago

5 0

Number 3 is b. petrologist
Number 4 is a.metamorphic

Ilya [14]4 years ago

5 0

1.d
3.b
4.a
5.f
hope this helped

You might be interested in

When evaluating data, why is it better to make a graph instead of just looking at the raw data in the table?(8th grade Science s

ziro4ka [17]

Answer:All professors planned and thought about data before graph construction. When reflecting on their graphs, professors and graduate students focused on the ... feel more inclusive in the learning process and gain better science process skills, ... We organized data in a table instead of a paragraph with numbers

Explanation:

hope that helps

3 0

3 years ago

When light hits a red wagon, some of the energy is absorbed and ______.

ZanzabumX [31]

Answer: A. Red light is reflected

Explanation:

8 0

3 years ago

6. During an impact time casting 5 x 10-45 a gulf club exerts an average impar

Novay_Z [31]

Answer:

2.5 × 10-⁴¹ Ns

Explanation:

Impulse

I = F × t

I = 5000 N × 5 × 10-⁴⁵ s

I = 25 × 10-⁴² Ns

I = 2.5 × 10-⁴¹ Ns

#LearnWithEXO

6 0

3 years ago

Velocity is described by __ and time

klasskru [66]

Answer:

direction and time

Explanation:

4 0

4 years ago

A muon has a rest mass energy of 105.7 MeV, and it decays into an electron and a massless particle. If all the lost mass is conv

sergeinik [125]

Answer:

The electron’s velocity is 0.9999 c m/s.

Explanation:

Given that,

Rest mass energy of muon = 105.7 MeV

We know the rest mass of electron = 0.511 Mev

We need to calculate the value of γ

Using formula of energy

$K_{rel}=(\gamma-1)mc^2$

$\dfrac{K_{rel}}{mc^2}=\gamma-1$

Put the value into the formula

$\gamma=\dfrac{105.7}{0.511}+1$

$\gamma=208$

We need to calculate the electron’s velocity

Using formula of velocity

$\gamma=\dfrac{1}{\sqrt{1-(\dfrac{v}{c})^2}}$

$\gamma^2=\dfrac{1}{1-\dfrac{v^2}{c^2}}$

$\gamma^2-\gamma^2\times\dfrac{v^2}{c^2}=1$

$v^2=\dfrac{1-\gamma^2}{-\gamma^2}\times c^2$

Put the value into the formula

$v^2=\dfrac{1-(208)^2}{-208^2}\times c^2$

$v=c\sqrt{\dfrac{1-(208)^2}{-208^2}}$

$v=0.9999 c\ m/s$

Hence, The electron’s velocity is 0.9999 c m/s.

6 0

3 years ago