Please answer this question
2 answers:
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Answer:
The radius of the gold nucleus is 7.1x10⁻¹⁵m
Explanation:
The nearest distance is:
(eq. 1)
Where
z = atomic number of gold = 79
e = electron charge = 1.6x10⁻¹⁹C
k = electrostatic constant = 9x10⁹Nm²C²
energy of the particle = 32 MeV = 5.12x10⁻¹²J
At the potential energy is zero, all the energy will be kinetic energy:
Where
m = 4 mp = mass of proton
Replacing in equation 1
Answer:
4.14°
Explanation:
given:
r = 1.2 km
v = 105 km/h
1) <em>convert your given </em>
a) r = 1.2 km to m = 1200m
b) v = 105 km/h to m/s = 29.2 m/s
2) <em>plug into your ideal banking angle equation</em>
(
) =
= 4.14°