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3 years ago

8

A viscous coating that surrounds the olfactory hairs

1 answer:

Alex17521 [72]3 years ago

6 0

A viscous coating that surrounds the olfactory hairs is called mucous layer!

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The Moon is made up mostly of _______, similar to minerals on Earth.

yawa3891 [41]

The moon is made up mostly of Silicates, hope this answer helps.

3 0

3 years ago

Read 2 more answers

A stone is thrown vertically up. What kind of energy did the stone have initially? What happens to this energy as the stone asce

Alex

Answer:

kinetic energy at first

Explanation:

kinetic turns to potential as it gains height

7 0

4 years ago

A uniform, 4.5 kg, square, solid wooden gate 2.0 mm on each side hangs vertically from a frictionless pivot at the center of its

True [87]

Answer:

The angular velocity is $w = 1.43\ rad/sec$

Explanation:

From the question we are told that

The mass of wooden gate is $m_g = 4.5 kg$

The length of side is L = 2 m

The mass of the raven is $m_r = 1.2 kg$

The initial speed of the raven is $u_r = 5.0m/s$

The final speed of the raven is $v_r = 1.5 m/s$

From the law of conservation of angular momentum we express this question mathematically as

Total initial angular momentum of both the Raven and the Gate = The Final angular momentum of both the Raven and the Gate

The initial angular momentum of the Raven is $m_r * u_r * \frac{L}{2}$

Note: the length is half because the Raven hit the gate at the mid point

The initial angular momentum of the Gate is zero

Note: This above is the generally formula for angular momentum of square objects

The final angular velocity of the Raven is $m_r * v_r * \frac{L}{2}$

The final angular velocity of the Gate is $\frac{1}{3} m_g L^2 w$

Substituting this formula

$m_r * u_r * \frac{L}{2} = \frac{1}{3} m_g L^2 w + m_r * v_r * \frac{L}{2}$

$\frac{1}{3} m_g L^2 w = m_r * v_r * \frac{L}{2} - m_r * u_r * \frac{L}{2}$

$\frac{1}{3} m_g L^2 w = m_r * \frac{L}{2} * [u_r - v_r]$

Where $w$ is the angular velocity

Substituting value

$\frac{1}{3} (4.5)(2)^2 w = 1.2 * \frac{2}{2} * [5 - 1.5]$

$6w = 4.2$

$w = \frac{6}{4.2}$

$w = 1.43\ rad/sec$

5 0

3 years ago

A solid metal ball with a mass of 10.0 kg is placed on a smooth floor what force would be needed to accelerate the ball at a rat

miv72 [106K]

20n no doubt because the 10.0 / 2.0

7 0

3 years ago

The escape velocity on earth is 11.2 km/s. What fraction of the escape velocity is the rms speed of H2 at a temperature of 31.0

Sveta_85 [38]

To solve this problem it is necessary to apply the concept related to root mean square velocity, which can be expressed as

$v_{rms} = \sqrt{\frac{3RT}{n}}$

Where,

T = Temperature

R = Gas ideal constant

n = Number of moles in grams.

Our values are given as

$v_e =11.2km/s = 11200m/s$

The temperature is

$T = 30\°C = 30+273 = 303K$

Therefore the root mean square velocity would be

$v_{rms} = \sqrt{\frac{3(8.314)(303)}{0.002}}$

$v_{rms} = 1943.9m/s$

The fraction of velocity then can be calculated between the escape velocity and the root mean square velocity

$\alpha = \frac{v_{rms}}{v_e}$

$\alpha = \frac{1943.9}{11200}$

$\alpha = 0.1736$

Therefore the fraction of the scape velocity on the earth for molecula hydrogen is 0.1736

7 0

3 years ago