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MrRissso [65]
2 years ago
5

A block with a mass of 33.0 kg is pushed with a horizontal force of 150 N. The block moves at a constant speed across a level, r

ough surface a distance of 4.95 m.
(a) What is the work done (in J) by the 150 N force?

_________J

(b) What is the coefficient of kinetic friction between the block and the surface?
________
Physics
1 answer:
lord [1]2 years ago
4 0

The work done is given by 742.5 J while the coefficient of kinetic friction between the block and the surface is 0.46.

<h3>What is the work done?</h3>

The work done is given by the use of the formula;

W = F * x

Where;

F = force applied

x = distance covered

W = 150 N *  4.95 m = 742.5 J

Now;

The coefficient of kinetic friction is given by;

μ = F/mg

μ = 150/ 33 * 9.8

μ = 0.46

Learn more about work done:brainly.com/question/13662169

#SPJ1

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During tug-of-war, team A does 2.20*10^5 J of work in pulling team B 8.00m. What average force did team A exert
Talja [164]

As we know that work done is defined as product of force and displacement

so here we will have

W = F.d

so here we know that

W = 2.20 \times 10^5 J

also we know that

d = 8.00 m

now we will have

2.20 \times 10^5 = F(8.00)

F = \frac{2.20 \times 10^5}{8}

F = 27500 N

so it will have 27500 N force on it

4 0
3 years ago
Plz help me!!!! A spring is connected to a wall as shown below. A mass on a horizontal surface is connected to the springs and p
kirill [66]

Answer:

320 N/m

Explanation:

F = k·Δx

where

F is the restoring force of the spring

k is the proportionality constant called the ‘spring constant’

Δx is the change in the spring’s position due to the deformation.

You need the k so

25 cm= 0.25m

k=F/∆x = 80/0.25 = 320 N/m

6 0
3 years ago
A well is being dug. A 4.5-kg bucket is filled with 28.0 kg of dirt and pulled vertically upward at a constant speed through a d
andreyandreev [35.5K]

The work done on the filled bucket in raising out of the hole is 2, 925 Joules

<h3>How to determine the work done</h3>

Using the formula:

Work done = force * distance

Note that force = mass * acceleration

F = mg + ma

F = 4. 5 * 10 + 28 * 10

F = 45 + 280

F = 325 Newton

Distance = 9m

Substitute into formula

Work done = 325 * 9

Work done = 2, 925 Joules

Therefore, the work done is 2, 925 Joules

Learn more about work done here:

brainly.com/question/25573309

#SPJ1

4 0
2 years ago
Which number below equals 129000? * *
solong [7]

Answer:

0.1

Explanation:

5 0
3 years ago
Physic help????????????????
maxonik [38]

My personal understanding and opinion is that ALL of those questions
should be part of an assessment of Physical Activity Readiness.


4 0
3 years ago
Read 2 more answers
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