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nekit [7.7K]
3 years ago
5

If the vertical axis and time on the horizontal axis if the speed is steadily increasing could the speef line ever become perfec

tly vertical
Physics
1 answer:
Phantasy [73]3 years ago
8 0

A graph of real speed can have a section that's as steep as you want,
but it can never be a perfectly vertical section.

Any vertical line on a graph, even it it's only a tiny tiny section, means
that at that moment in time, the speed had many different values.

It also means that the speed took no time to change from one value to
another, and THAT would mean infinite acceleration.

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The Earth’s radius is 6378.1 kilometers. If you were standing at the equator, you are essentially undergoing uniform circular mo
emmainna [20.7K]

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b. 84 minutes

Explanation:

a_c=g = Centripetal acceleration = 9.81 m/s²

r = Radius of Earth = 6378.1 km

v = Velocity

Centripetal acceleration is given by

a_c=\dfrac{v^2}{r}\\\Rightarrow v=\sqrt{a_cr}\\\Rightarrow v=\sqrt{9.81\times 6378100}\\\Rightarrow v=7910.06706\ m/s

Time period is given by

T=\dfrac{2\pi r}{v60}\\\Rightarrow T=\dfrac{2\pi 6378.1\times 10^3}{7910.06706\times 60}\\\Rightarrow T=84.43835\ minutes

The time period of Earth’s rotation would be 84.43835 minutes

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What are the factor that affect gravity​
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The factors that affect gravity are as follows:

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A softball player moving 3.89 m/s
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Answer:

0.119 s is the correct answer to this question.

Explanation:

As mentioned in the question

U=3.89\ m/s

a=-1.44\ m/s^2

S=4.8\ m

Consider the final speed of the softball covering the distance of 4.8m is v

Now using the equation

v^2=U^2+2aS

Putting the value of U, A, S in the previous equation we get

V^2=3.89^2-2\times 1.44\times 4.8\\V=3.7\ m/s\\

Now again using the equation

v=U+at

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Substituting the value of v, U, a

3.7=3.89-1.44\times t\\t=0.119\ s\\

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