The distance from Humood's house to the school is 500m
<h3>How to determine the distance from Humood's house to the school?</h3>
The given parameters are:
Humood's house is (-5,7)
The school is (3,1)
The distance between both points is calculated using
Substitute the known values in the above equation
Evaluate
d = 10
Each unit in the graph is 50m.
So, we have
Distance =10 * 50m
Evaluate the product
Distance = 500m
Hence, the distance from Humood's house to the school is 500m
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∠ABC = 101°(given) so y + x = 101°: 25° + x = 180° → x = 76°
p & w are alternate interior angles so are congruent: w = p = 27°
y & z are alternate interior angles so are congruent: z = y = 25°
z, w, E is a triangle so sum is equal to 180°: 25° + 27° + E = 180°→ E = 126°
E & e are supplementary so sum is equal to 180°: 126° + e = 180°→ e = 54°
x, e, n is a triangle so sum is equal to 180°: 76° + 54° + n = 180°→ n = 50°
Answer: n=50°, w=27°, x=76°, z=25°
The answer to this question is:
<span>Which form of cell division plays a key role in sexual reproduction?
</span><span>B-"Meiosis"
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Answer:B
Step-by-step explanation:
Using what is known as the "Triangle Inequality Theorem" a+b can not be less than c or else it is not a triangle. (A and B are the smallest sides of the triangle).
A) 6cm + 15cm = 21cm which is less than 23cm: Not a triangle
B) 5cm + 9cm = 14cm which is greater than 13cm: This makes a triangle and therefore the answer is B
C) 5cm + 8cm = 13cm which is less than 13cm: Not a triangle