Explanation:
We are given: entropy of Fe2O3 = 90J/K.mol
: entropy of C = 5.7J/K.mol
: entropy of Fe = 27.2J/K.mol
: entropy of CO = 198J/K.mol
Answer:
The correct answer is C.
Answer: FeO is called ferrous oxide while Fe2O3 is ferric oxide
Explanation:
Ferrous oxide, commonly known as iron(II) oxide contains iron that lost 2 elections in the oxidation process. So it is able to bond with other atoms that have an extra 2 electrons to share. Ferric oxide, is commonly known as iron(III) oxide
Answer:
79.7%
Explanation:
Percent yield of reaction is defined as the ratio between theoretical yield of a reaction and actual yield obtained.
In the problem, theoretical yield are 6 moles of KNO₃ and actual yield are 4.78 moles. Thus, percent yield is:
4.78 mol / 6 mol × 100 =<em> 79.7%</em>
