laboratory stock solution is 1.50 M NaOH. Calcul. Show transcribed image text A laboratory stock solution is 1.50 M NaOH. Calculate the volume of this stock solution that would be needed to prepare 300. ml
To answer this question, you need to know the molecular weight of zinc so you can determine how many mol zinc you have. Zinc molecular weight is 65.38gram/mol. Then the calculation would be: 48.3gram/(<span>65.38gram/mol)= 0.74 mol
Since you are asked the amount of atom, you need to multiply the unit in mole with Avogadro number. The calculation should be: 0.74 * 6.02 * 10^23= 4.45* 10^23 molecules</span>
Answer:I believe the correct answer from the choices listed above is option D. A
Explanation:neutral atom possesses an atomic number of 15 and an atomic mass of 31.Three electrons are gained. This conversion results to a negatively charged ion.
Write the symbols for the cation and the anion: Mg and Cl.
Determine the charge on the cation and anion. If the cation has a Roman numeral after it, that is the charge on that cation. ...
Determine formula.
Cr2O72- + 6CH3OH + 8H+ --- > 6CH2O + 2Cr3+ + 7H2O
