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evablogger [386]
3 years ago
6

A solution of NaCl ( aq ) is added slowly to a solution of lead nitrate, Pb ( NO 3 ) 2 ( aq ) , until no further precipitation o

ccurs. The precipitate is collected by filtration, dried, and weighed. A total of 10.55 g PbCl 2 ( s ) is obtained from 200.0 mL of the original solution. Calculate the molarity of the Pb ( NO 3 ) 2 ( aq ) solution.
Chemistry
1 answer:
3241004551 [841]3 years ago
4 0

Answer:

The molarity of the Pb(NO_3)_2 solution = 0.1895 M

Explanation:

The mass of the PbCl_2 obtained = 10.55 g

Molar mass of PbCl_2 = 278.1 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{10.55\ g}{278.1\ g/mol}

Moles_{PbCl_2}= 0.0379\ mol

From the reaction:-

Pb(NO_3)_2+2NaCl\rightarrow PbCl_2+2NaNO_3

1 mole of PbCl_2 is produced from 1 mole of Pb(NO_3)_2

Also,

0.0379 mole of PbCl_2 is produced from 0.0379 mole of Pb(NO_3)_2

Mole of Pb(NO_3)_2 = 0.0379 mol

Volume = 200.0 mL = 0.2 L ( 1 mL = 0.001 L )

Molarity is defined as the number of moles present in one liter of the solution. It is basically the ratio of the moles of the solute to the liters of the solution.

The expression for the molarity, according to its definition is shown below as:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Thus,

Molarity=\frac{0.0379}{0.2}\ M = 0.1895\ M

<u>The molarity of the Pb(NO_3)_2 solution = 0.1895 M</u>

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Answer:

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Explanation:

Given:

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= 5.90499 ≈ 6 stages

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