Answer:
Explanation:
I did this class yesterday give me like 10min imma find my anwsers
Answer: The empirical formula for C6H12O6 is CH2O. Every carbohydrate, be it simple or complex, has an empirical formula CH2O
Explanation:
Answer:
Explanation:
Upon arrival we needed to hunt in this new land we only had five refills and they needed 50 g of gunpowder to be shot once. We only have 15 pounds of gunpowder. It is taking six shots to kill one of these wild turkeys. How many turkeys can be shot with 15 pounds of gunpowder?
If we had plenty of refills, and it takes 6 shots to kill a wild turkey at 50 gms of gunpowder per shot, then each turkey requires 6X50 =300gms of gunpowder. We have 15X454 gms of gunpowder and have the potential to kill 15X454/300=22.7 or 22 turkeys.and it takes 6 shots to kill a wild turkey.
The limiting reagent is the number of refills, and withonly 5, we are out of luck and can't kill one turkey
Answer:
17.55 g of NaCl
Explanation:
The following data were obtained from the question:
Molarity = 3 M
Volume = 100.0 mL
Mass of NaCl =..?
Next, we shall convert 100.0 mL to L. This can be obtained as follow:
1000 mL = 1 L
Therefore,
100 mL = 100/1000
100 mL = 0.1 L
Therefore, 100 mL is equivalent to 0.1 L.
Next, we shall determine the number of mole NaCl in the solution. This can be obtained as follow:
Molarity = 3 M
Volume = 0.1 L
Mole of NaCl =?
Molarity = mole /Volume
3 = mole of NaCl /0.1
Cross multiply
Mole of NaCl = 3 × 0.1
Mole of NaCl = 0.3 mole
Finally, we determine the mass of NaCl required to prepare the solution as follow:
Mole of NaCl = 0.3 mole
Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol
Mass of NaCl =?
Mole = mass /Molar mass
0.3 = mass of NaCl /58.5
Cross multiply
Mass of NaCl = 0.3 × 58.5
Mass of NaCl = 17.55 g
Therefore, 17.55 g of NaCl is needed to prepare the solution.
