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fenix001 [56]
3 years ago
12

A ball with a mass of 5 kg is acted upon by a force of 20 N. If the ball begins moving from a velocity of 0 m/s and accelerates

for 2 seconds, what is its change in velocity?
A. 0 m/s B. 2 m/s C. 4 m/s. D. 8 m/s
Physics
1 answer:
Strike441 [17]3 years ago
8 0
The answer is d

F=ma. so by substituting we find that a=4

and a=vi-vf/t

by substiting we find vf=8

so the difference is vf-vi = 8m/s
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blondinia [14]
Average speed = total distance travelled ÷ total time taken

AS = (75km + 68km) ÷ (1hr + 2hr)

As = 143km ÷ 3hr

AS = 47.66667 km/hr

AS = 47.7 km/hr (3sf)
8 0
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Electrically inert metal ball A is connected to the ground by a wire. What happens to the charge of this ball if you bring a neg
kaheart [24]

Explanation:

They will repel, meaning that they are made of an electrical conductor.

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A sprinter who is running a 200-m race travels the second 100 m in much less time than the first 100m because
Harrizon [31]

Answer:

He is warmed up now

Explanation:

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3 0
3 years ago
Read 2 more answers
An atom of carbon has a radius of 67.0 pm and the average orbital speed of the electrons in it is about 1.3 x 10⁶ m/s.
adoni [48]

Answer :

The least possible uncertainty in an electron's velocity is, 4.32\times 10^{5}m/s

The percentage of the average speed is, 33 %

Explanation :

According to the Heisenberg's uncertainty principle,

\Delta x\times \Delta p=\frac{h}{4\pi} ...........(1)

where,

\Delta x = uncertainty in position

\Delta p = uncertainty in momentum

h = Planck's constant

And as we know that the momentum is the product of mass and velocity of an object.

p=m\times v

or,

\Delta p=m\times \Delta v      .......(2)

Equating 1 and 2, we get:

\Delta x\times m\times \Delta v=\frac{h}{4\pi}

\Delta v=\frac{h}{4\pi \Delta x\times m}

Given:

m = mass of electron = 9.11\times 10^{-31}kg

h = Planck's constant = 6.626\times 10^{-34}Js

radius of atom = 67.0pm=67.0\times 10^{-12}m     (1pm=10^{-12}m)

\Delta x = diameter of atom = 2\times 67.0\times 10^{-12}m=134.0\times 10^{-12}m

Now put all the given values in the above formula, we get:

\Delta v=\frac{6.626\times 10^{-34}Js}{4\times 3.14\times (134.0\times 10^{-12}m)\times (9.11\times 10^{-31}kg)}

\Delta v=4.32\times 10^{5}m/s

The minimum uncertainty in an electron's velocity is, 4.32\times 10^{5}m/s

Now we have to calculate the percentage of the average speed.

Percentage of average speed = \frac{\text{Uncertainty in speed}}{\text{Average speed}}\times 100

Uncertainty in speed = 4.32\times 10^{5}m/s

Average speed = 1.3\times 10^{6}m/s

Percentage of average speed = \frac{4.32\times 10^{5}m/s}{1.3\times 10^{6}m/s}\times 100

Percentage of average speed = 33.2 % ≈ 33 %

Thus, the percentage of the average speed is, 33 %

3 0
3 years ago
URGENT PLEASE HELP!!!! GIVING BRAINLIEST!! If you answer this correctly ill answer some of your questions you have posted! (29pt
Furkat [3]

Chemical=B

Mechanical=C

Nuclear=A

Electromagnetic=D

Thermal=E

I think these are right but if not I’m sorry

Hope I helped :]

5 0
2 years ago
Read 2 more answers
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