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anzhelika [568]

3 years ago

10

How much force is required to accelerate a 4 kg bowling ball from 0 m/s to 2 m/s in 1 second? what amount of energy does the bow

ling ball gain? how much work was done on the bowling ball?

1 answer:

Vladimir [108]3 years ago

5 0

Well, F = ma

and a= change in vel / change in time
= (2-0 ) / 1 = 2 m^2/s

so, F= 4* 2 = 8 N

and W = F.S = 8 * 2 = 16 J

hope it helped

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Two identical positive charges are placed near each other. At the point halfway between the two chargesTwo identical positive ch

Nitella [24]

Answer:The electric field is zero and the potential is positive.

Explanation:

Two identical positive charges are separated by a certain distance and midway between charges two identical positive charges are placed near each other.

So the Electric field at midway is zero because the electric field due to both charges add up to give zero electric field.(because they point in opposite direction)

Potential is scalar quantity and charges are positive so they add up to give potential.

7 0

2 years ago

A particularly beautiful note reaching your ear from a rare stradivarius violin has a wavelength of 39.1 cm. the room is slightl

raketka [301]

The wavelength of the note is $\lambda = 39.1 cm = 0.391 m$ . Since the speed of the wave is the speed of sound, $c=344 m/s$ , the frequency of the note is
$f= \frac{c}{\lambda}=879.8 Hz$

Then, we know that the frequency of a vibrating string is related to the tension T of the string and its length L by
$f= \frac{1}{2L} \sqrt{ \frac{T}{\mu} }$
where $\mu=0.550 g/m = 0.550 \cdot 10^{-3} kg/m$ is the linear mass density of our string.
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$L= \frac{1}{2f} \sqrt{ \frac{T}{\mu} } =0.31 m$

8 0

3 years ago

Please !!! I really need help !!! How do I understand these ?!!!!

trasher [3.6K]

Answer

The answer for the first one I think is false.

The second one would be true i think. I hope i got it right and have a wonderful day

8 0

2 years ago

Read 2 more answers

A charged wire of negligible thickness has length 2L units and has a linear charge density λ. Consider the electric field E-vect

Stels [109]

Answer:

$E=2K\lambda d\dfrac{L }{d^2\sqrt{L^2+d^2}}$

Explanation:

Given that

Length= 2L

Linear charge density=λ

Distance= d

K=1/(4πε)

The electric field at point P

$E=2K\int_{0}^{L}\dfrac{\lambda }{r^2}dx\ sin\theta$

$sin\theta =\dfrac{d}{\sqrt{d^2+x^2}}$

$r^2=d^2+x^2$

So

$E=2K\lambda d\int_{0}^{L}\dfrac{dx }{(x^2+d^2)^{\frac{3}{2}}}$

Now by integrating above equation

$E=2K\lambda d\dfrac{L }{d^2\sqrt{L^2+d^2}}$

4 0

3 years ago

After Gru shrinks the moon are the side effects realistic to what would happen if the moon actually shrunk? Explain.

Elena-2011 [213]

Answer: No, water in the ocean wouldn't have tides wouldn't be as strong anymore.

Explanation:

7 0

2 years ago