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anzhelika [568]

3 years ago

10

How much force is required to accelerate a 4 kg bowling ball from 0 m/s to 2 m/s in 1 second? what amount of energy does the bow

ling ball gain? how much work was done on the bowling ball?

1 answer:

Vladimir [108]3 years ago

5 0

Well, F = ma

and a= change in vel / change in time
= (2-0 ) / 1 = 2 m^2/s

so, F= 4* 2 = 8 N

and W = F.S = 8 * 2 = 16 J

hope it helped

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You are traveling in a car toward a hill at a speed of 36.4 mph. The car's horn emits sound waves of frequency 231 Hz, which mov

Marina CMI [18]

Answer:

<em>a. The frequency with which the waves strike the hill is 242.61 Hz</em>

<em>b. The frequency of the reflected sound wave is 254.23 Hz</em>

<em>c. The beat frequency produced by the direct and reflected sound is </em>

<em> 11.62 Hz</em>

Explanation:

Part A

The car is the source of our sound, and the frequency of the sound wave it emits is given as 231 Hz. The speed of sound given can be used to determine the other frequencies, as expressed below;

$f_{1} = f[\frac{v_{s} }{v_{s} -v} ]$ ..............................1

where $f_{1}$ is the frequency of the wave as it strikes the hill;

f is the frequency of the produced by the horn of the car = 231 Hz;

$v_{s}$ is the speed of sound = 340 m/s;

v is the speed of the car = 36.4 mph

Converting the speed of the car from mph to m/s we have ;

hint (1 mile = 1609 m, 1 hr = 3600 secs)

v = $36.4 mph *\frac{1609 m}{1 mile} *\frac{1 hr}{3600 secs}$

v = 16.27 m/s

Substituting into equation 1 we have

$f_{1}$ = $231 Hz (\frac{340 m/s}{340 m/s - 16.27 m/s})$

$f_{1}$ = 242.61 Hz.

Therefore, the frequency which the wave strikes the hill is 242.61 Hz.

Part B

At this point, the hill is the stationary point while the driver is the observer moving towards the hill that is stationary. The frequency of the sound waves reflecting the driver can be obtained using equation 2;

$f_{2} = f_{1} [\frac{v_{s}+v }{v_{s} } ]$

where $f_{2}$ is the frequency of the reflected sound;

$f_{1}$ is the frequency which the wave strikes the hill = 242.61 Hz;

$v_{s}$ is the speed of sound = 340 m/s;

v is the speed of the car = 16.27 m/s.

Substituting our values into equation 1 we have;

$f_{2} = 242.61 Hz [\frac{340 m/s+16.27 m/s }{340 m/s } ]$

$f_{2}$ = 254.23 Hz.

Therefore, the frequency of the reflected sound is 254.23 Hz.

Part C

The beat frequency is the change in frequency between the frequency of the direct sound and the reflected sound. This can be obtained as follows;

Δf = $f_{2}$ - $f_{1}$

The parameters as specified in Part A and B;

Δf = 254.23 Hz - 242.61 Hz

Δf = 11.62 Hz

Therefore the beat frequency produced by the direct and reflected sound is 11.62 Hz

3 0

3 years ago

Movement of a stationary object

Setler [38]

I would say that you're describing an impossible situation.
If the object is stationary, then it has no movement.
If the object has movement, then it's not stationary.

5 0

4 years ago

The ratio between the volumes of two spheres is 27 to 8. what is the ratio between their respective radii?

kiruha [24]

Plz see the attachment...

7 0

4 years ago

A car starts from rest and accelerates along a straight line path in one minute it finally attains a velocity of 40 meters/secon

strojnjashka [21]

|Average acceleration| = (change in speed) / (time for the change)

Change in speed = (speed at the end) minus (speed at the beginning)

= (40 m/s) - ( 0 )

= 40 m/s .

|Average acceleration| = (40 m/s) / (60 sec) = 2/3 m/s² .

6 0

3 years ago

Which type of planets have the most moons? Where did these moons likely originate?

Elan Coil [88]

Answer:

<u>Jupiter and Saturn</u>

Explanation:

Giant planets -

Giants planets have maximum moons ,

for example ,

Jupiter and Saturn .

Jupiter have 63 moons ( according to 2009 calculation ) , where , 8 moons are the regular satellites , 4 moons are spherical and large , 4 moons are small and close to Jupiter , in addition to it Jupiter have 55 irregular satellites .

Second highest moon is with planet Saturn , with 61 moons .

Many of moon's are thought to have been captured from the small-body population during the formation of the solar system .

4 0

4 years ago