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Yanka [14]
3 years ago
14

company uses a ramp to slide boxes of parts to a shippingarea. Each box weighs about 10 kilograms. When sliding downthe ramp, th

e boxes accelerate at a speed of 0.1 m/sec2. What isthe force acting on each box? For this problem, ignore theeffects of friction acting on each box.
Physics
1 answer:
Inessa [10]3 years ago
8 0

Answer:

Fₓ = 1 N

Explanation:

For this exercise let's use Newton's second law, in this case our reference system has an axis parallel to the plane, we will call it the x-axis and we assume that the downward direction is positive, an y- axis perpendicular to the plane. Let's write Newton's second law for each axis

x axis

        Wₓ = m a

y Axis

        N - W_y =

        N = W_y

let's use trigonometry to find the components of the weight

         sin θ = Wₓ / W

         Wx = W sin  θ

          cos  θ = W_y / W

         W_y = W cos  θ

we substitute

        Fₓ = mg sin  θ = m a

        Fₓ = 10 0.1

        Fₓ = 1 N

           

           

This is the force that makes the box slide down and a component of the box's weight.

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Amanda [17]

Answer:

respiratory = nose

circulatory = heart

digestive = mouth

nervous = brain

5 0
3 years ago
An object travels 7.5 m/s toward the west . Under the influence of a constant net force of 5.2 kN, it comes to rest in 3.2 s. Wh
Softa [21]

Answer:

m = 2218.67 kg

Explanation:

It is given that,

Initial velocity, u = 7.5 m/s

Final speed of an object, v = 0 (at rest)

Force, F = 5.2 kN

Time, t = 3.2 s

We need to find the mass of the object. Force acting on an object is given by :

F = ma

m is mass, a is acceleration

F=\dfrac{m(v-u)}{t}\\\\m=\dfrac{Ft}{v-u}\\\\m=\dfrac{5.2\times 10^3\times 3.2}{0-7.5}\\\\m=2218.67\ kg

So, the mass of the object is 2218.67 kg

5 0
3 years ago
5. If the total charge of an atom's nucleus is +3 and the total charge of the surrounding electrons is -3, the atom
tekilochka [14]

Answer:

i believe the answer is d.

Explanation:

its either d or its c. but based off of the fact the it is the only one with a positive charge and the one around it are negative then its most likely d.

8 0
4 years ago
A 0.290 cm diameter plastic sphere, used in a static electricity demonstration, has a uniformly distributed 30.0 pC charge on it
mojhsa [17]

Answer:

Therefore,

The potential (in V) near its surface is 186.13 Volt.

Explanation:

Given:

Diameter of sphere,

d= 0.29 cm

radius=\dfrac{d}{2}=\dfrac{0.29}{2}=0.145\ cm

r = 0.145\ cm = 0.145\times 10^{-2}\ m

Charge ,

Q = 30.0\ pC=30\times 10^{-12}

To Find:

Electric potential , V = ?

Solution:

Electric Potential at point surface is given as,

V=\dfrac{1}{4\pi\epsilon_{0}}\times \dfrac{Q}{r}

Where,  

V= Electric potential,  

ε0 = permeability free space = 8.85 × 10–12 F/m

Q = Charge  

r = Radius  

Substituting the values we get

V=\dfrac{1}{4\times 3.14\times 8.85\times 10^{-12}}\times \dfrac{30\times 10^{-12}}{0.145\times 10^{-2}}

V=\dfrac{30}{16.117\times 10^{-2}}=186.13\ Volt

Therefore,

The potential (in V) near its surface is 186.13 Volt.

3 0
4 years ago
g Two balls of equal size are dropped from the same height from the roof of a building. The mass of ball A is twice that of ball
tamaranim1 [39]

Answer:

K_A = 2K_B

Explanation:

As we know that initial height of both the balls are same

also the mass of the two balls is given as

m_A = 2m_B

so here we can say by mechanical energy conservation

initial total mechanical energy = final total mechanical energy

since both balls are initially at rest so initial total kinetic energy of the balls will be zero

now final total kinetic energy = initial total potential energy

now we say

K_A = m_A gh

K_B = m_B gh

so we have

\frac{K_A}{K_B} = \frac{m_A}{m_B}

K_A = 2K_B

5 0
3 years ago
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