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Yanka [14]
2 years ago
14

company uses a ramp to slide boxes of parts to a shippingarea. Each box weighs about 10 kilograms. When sliding downthe ramp, th

e boxes accelerate at a speed of 0.1 m/sec2. What isthe force acting on each box? For this problem, ignore theeffects of friction acting on each box.
Physics
1 answer:
Inessa [10]2 years ago
8 0

Answer:

Fₓ = 1 N

Explanation:

For this exercise let's use Newton's second law, in this case our reference system has an axis parallel to the plane, we will call it the x-axis and we assume that the downward direction is positive, an y- axis perpendicular to the plane. Let's write Newton's second law for each axis

x axis

        Wₓ = m a

y Axis

        N - W_y =

        N = W_y

let's use trigonometry to find the components of the weight

         sin θ = Wₓ / W

         Wx = W sin  θ

          cos  θ = W_y / W

         W_y = W cos  θ

we substitute

        Fₓ = mg sin  θ = m a

        Fₓ = 10 0.1

        Fₓ = 1 N

           

           

This is the force that makes the box slide down and a component of the box's weight.

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510 g squirrel with a surface area of 935 cm2 falls from a 4.8-m tree to the ground. Estimate its terminal velocity. (Use the dr
Yuki888 [10]

Answer:

The terminal velocity is v_t  =17.5 \ m/s

Explanation:

From the question we are told that

       The mass of the squirrel is  m_s  =  50\ g  =  \frac{50}{1000} =  0.05 \  kg

      The surface area is   A_s =  935 cm^2  =  \frac{935}{10000} = 0.0935 \ m^2

       The height of fall is  h =4.8 m

        The length of the prism is l =  23.2 = 0.232 \ m

          The width of the prism is w =  11.6 =  0.116 \ m

 

The terminal velocity is mathematically represented as

       v_t  =  \sqrt{\frac{2 * m_s *  g }{\dho_s * C  * A } }

Where \rho  is the density of a rectangular prism with a constant values of \rho  =  1.21 \ kg/m^3

            C is the drag coefficient for a horizontal skydiver with a value = 1

            A  is the area of the prism the squirrel is assumed to be which is mathematically represented as

      A =  0.116 * 0.232

       A =  0.026912 \ m^2

 substituting values

      v_t  =  \sqrt{\frac{2 * 0.510 *  9.8 }{1.21 * 1  * 0.026912 } }

     v_t  =17.5 \ m/s

       

7 0
3 years ago
Motor oil , with a viscosity of 0 . 250 Ns / m2 , is flowing through a tube that has a radius of 5 . 00 mm and is 25 . 0 cm long
Thepotemich [5.8K]

Answer:

1.1775 x 10^-3 m^3 /s

Explanation:

viscosity, η = 0.250 Ns/m^2

radius, r = 5 mm = 5 x 10^-3 m

length, l = 25 cm = 0.25 m

Pressure, P = 300 kPa = 300000 Pa

According to the Poisuellie's formula

Volume flow per unit time is

V=\frac{\pi \times Pr^{4}}{8\eta l}

V=\frac{3.14 \times 300000\times \left ( 5\times 10^{-3} \right )^{4}}{8\times 0.250\times 0.25}

V = 1.1775 x 10^-3 m^3 /s

Thus, the volume of oil flowing per second is 1.1775 x 10^-3 m^3 /s.

3 0
3 years ago
Two ping pong balls have been painted with metallic paint and charged by contact with an Van de Graaff generator. The charge on
andre [41]

Answer:

0.035 N

Explanation:

Parameters given:

Charge q1 = -3.31x10^(-7) C

Charge q2 = -5.7x10^(-7) C.

Distance between them, R = 22 cm = 0.22 m

Electrostatic force between to particles is given as:

F = (k* q1 * q2) / R²

F = (9 * 10^9 * -3.31 * 10^(-7) * -5.7 * 10^(-7)) / 0.22²

F = 0.035 N

6 0
3 years ago
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Why are scientific models important?
Wittaler [7]

Answer:

Scientific models are representations of objects, systems or events and are used as tools for understanding the natural world. Models use familiar objects to represent unfamiliar things. Models can help scientists communicate their ideas, understand processes, and make predictions.

5 0
2 years ago
Under normal conditions, what color do we expect diamonds to be?​
Ann [662]
Under normal lighting conditions, most diamonds appear to be colorless the naked eye. Many consumers think that all diamonds are colorless, however, in reality, they come in a wide range of colors. Actualcolor differences are very subtle.
8 0
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