D. Two or more of the same type or different types of atoms.
Answer:
In the third step of the citric acid cycle, the oxidation of isocitrate takes place and one molecule of carbon dioxide is released.
Explanation:
In the first step of citric acid cycle, acetylCoA combines with a four-carbon molecule, oxaloacetate, forming a six-carbon molecule, citrate.
In the second step, the citrate in the presence of enzyme anicotase is converted into isocitrate.
<u>In the third step, the oxidation of isocitrate takes place and one molecule of carbon dioxide is released leaving behind one five-carbon molecule called as α-ketoglutarate. During this step, NAD⁺ is reduced to form NADH. </u>
<u>This is first round of the citric acid cycle that could possibly release a carbon atom originating from this acetyl CoA.</u>
On series of reaction, another carbon dioxide molecule also being relased and oxaloacetate is regenerated again.
Explanation:
<em>1s 2s 2p</em>
<em>1s 2s 2p1s2 2s1 </em>
<em>1s 2s 2p1s2 2s1 2 1 1</em>
<em>1s 2s 2p1s2 2s1 2 1 11s2 2s2 </em>
Answer:
<em>The energy of atomic orbitals increases as the principal quantum number, n, increases. In any atom with two or more electrons, the repulsion between the electrons makes energies of subshells with different values of I differ so that the energy of the orbitals increases within a shell in the order s< p <d<f. Figure 1 depicts how these two trends in increasing energy relate. The 1s orbital at the bottom of the diagram is the orbital with electrons of lowest energy. The energy increases as we move up to the 2s and then 2p, 3s, and 3p orbitals, showing that the increasing n value has more influence on energy than the increasing I value for small atoms. However, this pattern does not hold for larger atoms. The 3d orbital is higher in energy than the 4s orbital. Such overlaps continue to occur frequently as we move up the chart.</em>
It is located in the Stratosphere.