The balanced equation for the above reaction is as follows; C₆H₁₂O₆ + 6O₂ --> 6CO₂ + 6H₂O molar ratio of glucose to CO₂ is 1:6 the mass of glucose reacted - 24.0 g Number of glucose moles reacted - 24.0 g /180 g/mol = 0.133 mol Number of CO₂ formed when 0.133 mol of glucose reacted -0.133 x 6 = 0.798 mol since CO₂ is a gas we can use the ideal gas law equation to find the volume occupied PV = nRT where P - pressure - 0.960 atm x 101 325 Pa / atm = 97 272 Pa n - number of moles - 0.798 mol R - universal gas constant - 8.314 Jmol⁻¹K⁻¹ T - temperature in Kelvin - 273 + 37 °C = 310 K substituting the values in the equation 97 272 Pa x V= 0.798 mol x 8.314 Jmol⁻¹K⁻¹ x 310 K V = 21.1 dm³ volume occupied by CO₂ is 21.1 dm³
