<span>2.51 grams
You want to prepare 19.16 g of some solution which will have 13.1% of it's mass being sucrose. So we just need to perform some simple multiplication:
19.16g * 0.131 = 2.50996g
Rounding to 3 significant figures gives 2.51 g.</span>
When the enthalpy value is given, we can calculate how much heat is use or produces in a given equation.
67.6 kCal ---> 67.6 kCal= 1 mol of reaction
1 mol of reaction= 1 mol of CO (based on the coefficient)
so 1 mole of CO gives us 67.6 kCal of heat.
calculation:
1 mol CO
D would be your best bet because evaporation occurs when water is heated, it then vibrates and then magic!
A straight handle for easy use and a wide tip for scooping food
Answer:
Kc = 6x10⁻⁶
Explanation:
For the reaction:
4NH₃(g) + 3O₂(g) ⇄ 2N₂(g) + 6H₂O(g)
Kc is defined as:
Kc =[N₂]² [H₂O]⁶ / [NH₃]⁴ [O₂]³
The equilibrium concentrations of the gases is -Because volume of the container is 1.00L-:
[N₂] = 2X = 1.96x10⁻³; <em>X = 9.8x10⁻⁴</em>
[H₂O] = 6X; 6ₓ9.8x10⁻⁴ = 5.88x10⁻³
[NH₃] = 0.0150M - 4X = 0.01108M
[O₂] = 0.0150M - 3X = 0.01206M
Replacing in Kc expression:
Kc =[1.96x10⁻³]² [5.88x10⁻³]⁶ / [0.01108M]⁴ [0.01206M]³
<h3>Kc = 6x10⁻⁶</h3>
