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ivolga24 [154]
2 years ago
14

Help pls ill give extra points

Chemistry
1 answer:
r-ruslan [8.4K]2 years ago
3 0

Explanation:

im sorry but it depends on what the diagram looks like for the problem

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What volume of a 0.160 MM solution of KOHKOH must be added to 550.0 mLmL of the acidic solution to completely neutralize all of
puteri [66]

The given question is incomplete. The complete question is :

What volume of 0.160 M solution of KOH must be added to 550.0 mL of the acidic solution to completely neutralize all of the 0.150 M hydrochloric acid?

Answer: Volume in liters to three significant figures is 0.516 L

Explanation:

To calculate the volume of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HCl

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is KOH

We are given:

n_1=1\\M_1=0.50M\\V_1=550.0mL\\n_2=1\\M_2=0.160M\\V_2=?

Putting values in above equation, we get:

1\times 0.150\times 550.0=1\times 0.160\times V_2\\\\V_2=516mL=0.516L   (1L=1000ml)

Thus volume in liters to three significant figures is 0.516 L

6 0
3 years ago
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