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3 years ago

Help pls ill give extra points

Chemistry

1 answer:

r-ruslan [8.4K]3 years ago

3 0

Explanation:

im sorry but it depends on what the diagram looks like for the problem

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Add the polynomials (7x^3-2x^2-12)+(3x^3-8x^2+10x)

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Answer:

10 x ^3 − 10 x ^2 + 10 x − 12

Explanation:

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3 years ago

Which chemical property deals with the ability of a substance being able to

Fantom [35]

$\large\underline{\bf\red{Solution:-}}$

The chemical property deals with the ability of a substance being able to burn is called combustibility [ option b ] .

More to know :-

1) Combustion :-

Combustion is a chemical process in which a substance reacts rapidly with oxygen and gives out heat.

The fuel can be any one of the 3 states of matter that is - solid , liquid & gases .

Examples of combustible substances :-

Solid - Coal

Liquid - Petrol , Disel , etc.

Gas - Hydrogen , Oxygen , etc .

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3 years ago

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A backpacker collects snow at 0°C, and places it in a cooking pot on a camp stove. It takes 643 kJ of heat energy to melt the sn

frutty [35]

Answer:

mass (m) of the snow that the backpacker collected= 0.855 kg

Explanation:

Given that:

Q = 643 kJ = 643000 J

ΔHfusion = 6.02 kJ/mol = 6020 J/mol

number of mole of water H2O = $\frac{mass (m)}{18}$

c = 4.18 J/g⋅K

ΔT = 100 K

Since there is a phase change from solid to liquid; then :

$Q =$ $Q_s + Q_l$

ΔH = $\frac{q}{mol}$

However without the given mass; we substitute $\frac{m}{18}$ for the number of moles; so:

Q = $\delta H * \frac{m}{18}$ $+ m*c * \delta T$

$643000 =$ $6020 * \frac{m}{18}+ m * 4.18 * 100$

m = 855 g

m = 0.855 kg

mass (m) of the snow that the backpacker collected= 0.855 kg

8 0

3 years ago

Atomic orbitals represent the wave functions that correspond to the solutions to the Schrödinger equation. The orbitals, which d

agasfer [191]

Explanation:

I'll give you a real answer later need points for test questions sorry

3 0

3 years ago

The combustion of 0.25 mol of an unknown organic compound results in the release of 320 kJ of energy. Which of the compounds in

vichka [17]

Answer: C. ethanol

The enthalpy of combustion is the amount of heat produced when one mole of ethanol undergoes complete combustion at 25 ° C and 1 atmosphere pressure, yielding products also at 25 ° C and 1 atm.

The enthalpy of combustion of the unknown compound is

ΔH = - 320 kJ / 0.25 mol = - 1280 kJ / mol

To choose a probable compound according to this combustion enthalpy, we must evaluate the deviation in relation to the values reported in the literature for the three probable compounds (methane, ethylene and ethanol). The deviation (e%) will be calculated according to the following equation,

e% = ( | ΔHx - ΔH | / ΔHx ) x 100%

where ΔHx is the enthalpy of combustion of the probable compound.

The following table shows the combustion enthalpies of the probable compounds and their deviation in relation to the enthalpy of ΔH = - 1280 kJ / mol

Compound Enthalpy of combustion (kJ/mol) Deviation

Methane - 890.7 43.8%

Ehylene -1411.2 9.3%

Ethanol -1368.6 6.5%

According to the previous table, we can say that the most probable compound is ethanol, since it has the smallest deviation in relation to the experimental enthalpy value of combustion.

5 0

4 years ago

Read 2 more answers