SORRY i forgot but i think its A because the sun has a really strong gravitational pull
sorry and hope it helps
Answer:
Second option 6.3 N at 162° counterclockwise from
F1->
Explanation:
Observe the attached image. We must calculate the sum of all the forces in the direction x and in the direction y and equal the sum of the forces to 0.
For the address x we have:
![-F_3sin(b) + F_1 = 0](https://tex.z-dn.net/?f=-F_3sin%28b%29%20%2B%20F_1%20%3D%200)
For the address and we have:
![-F_3cos(b) + F_2 = 0](https://tex.z-dn.net/?f=-F_3cos%28b%29%20%2B%20F_2%20%3D%200)
The forces
and
are known
![F_1 = 5.7\ N\\\\F_2 = 1.9\ N](https://tex.z-dn.net/?f=F_1%20%3D%205.7%5C%20N%5C%5C%5C%5CF_2%20%3D%201.9%5C%20N)
We have 2 unknowns (
and b) and we have 2 equations.
Now we clear
from the second equation and introduce it into the first equation.
![F_3 = \frac{F_2}{cos (b)}](https://tex.z-dn.net/?f=F_3%20%3D%20%5Cfrac%7BF_2%7D%7Bcos%20%28b%29%7D)
Then
![-\frac{F_2}{cos (b)}sin(b)+F_1 = 0\\\\F_1 = \frac{F_2}{cos (b)}sin(b)\\\\F_1 = F_2tan(b)\\\\tan(b) = \frac{F_1}{F_2}\\\\tan(b) = \frac{5.7}{1.9}\\\\tan^{-1}(\frac{5.7}{1.9}) = b\\\\b= 72\°\\\\m = b +90\\\\\m= 162\°](https://tex.z-dn.net/?f=-%5Cfrac%7BF_2%7D%7Bcos%20%28b%29%7Dsin%28b%29%2BF_1%20%3D%200%5C%5C%5C%5CF_1%20%3D%20%5Cfrac%7BF_2%7D%7Bcos%20%28b%29%7Dsin%28b%29%5C%5C%5C%5CF_1%20%3D%20F_2tan%28b%29%5C%5C%5C%5Ctan%28b%29%20%3D%20%5Cfrac%7BF_1%7D%7BF_2%7D%5C%5C%5C%5Ctan%28b%29%20%3D%20%5Cfrac%7B5.7%7D%7B1.9%7D%5C%5C%5C%5Ctan%5E%7B-1%7D%28%5Cfrac%7B5.7%7D%7B1.9%7D%29%20%3D%20b%5C%5C%5C%5Cb%3D%2072%5C%C2%B0%5C%5C%5C%5Cm%20%3D%20b%20%2B90%5C%5C%5C%5C%5Cm%3D%20162%5C%C2%B0)
Then we find the value of ![F_3](https://tex.z-dn.net/?f=F_3)
![F_3 = \frac{F_1}{sin(b)}\\\\F_3 =\frac{5.7}{sin(72\°)}\\\\F_3 = 6.01 N](https://tex.z-dn.net/?f=F_3%20%3D%20%5Cfrac%7BF_1%7D%7Bsin%28b%29%7D%5C%5C%5C%5CF_3%20%3D%5Cfrac%7B5.7%7D%7Bsin%2872%5C%C2%B0%29%7D%5C%5C%5C%5CF_3%20%3D%206.01%20N)
Finally the answer is 6.3 N at 162° counterclockwise from
F1->
The magnitude of the resultant is
√ (22² + 2.2²) = √ (484 + 4.84) = √488.84 = 22.11 m/s .
The direction of the resultant is
tan⁻¹(22N / 2.2E) = tan⁻¹(10) = 5.71° east of north .
Answer:
0.572
Explanation:
First examine the force of friction at the slipping point where Ff = µsFN = µsmg.
the mass of the car is unknown,
The only force on the car that is not completely in the vertical direction is friction, so let us consider the sums of forces in the tangential and centerward directions.
First the tangential direction
∑Ft =Fft =mat
And then in the centerward direction ∑Fc =Ffc =mac =mv²t/r
Going back to our constant acceleration equations we see that v²t = v²ti +2at∆x = 2at πr/2
So going backwards and plugging in Ffc =m2atπr/ 2r =πmat
Ff = √(F2ft +F2fc)= matp √(1+π²)
µs = Ff /mg = at /g √(1+π²)=
1.70m/s/2 9.80 m/s² x√(1+π²)= 0.572
Deer depend on plants to survive because they are herbivores. Herbivores are animals that only eats plants and fruits in order to survive. Deer's meal includes grass and evergreen plants. If grass is unavailable, they eat whatever food like fallen leaves, twigs, bushes and other woody plants.