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Galina-37 [17]
2 years ago
6

Help me with the following problem

Physics
1 answer:
Snezhnost [94]2 years ago
6 0

The electric field at arbitrary point outside the sphere is determined as the E = σr³/k.

<h3>Electric field determined from Gauss law</h3>

The electric field of the surface is determined from Gauss law as shown below;

E ∫ds = Q/ε

E (4πr²) = Q/ε

E = Q/4πεr² . r

E = \frac{Q R}{4\pi \varepsilon r^3}

<h3>Electric field outside the sphere with dielectric with polarization</h3>

P = \frac{\sigma}{E} \\\\E = \frac{\sigma}{P}

E = \frac{\sigma}{k/r^3} \\\\E = \frac{\sigma r^3}{k}

where;

  • σ is dipole moment of atom of the metal
  • k is dielectric constant

Thus, the electric field at arbitrary point outside the sphere is determined as the E = σr³/k.

The complete question:

A metal sphere of radius R carries a total charge Q. outside the sphere is a dielectric with polarization p(f) k/r^3er. Determine the electric field at arbitrary point outside the sphere.

Learn more about electric field here: brainly.com/question/14372859

#SPJ1

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