A car starts from rest and accelerates at 9 m/s². After 240 m. the final speed is 66 m/s.
<h3>What is Uniformly Accelerated Motion?</h3>
Uniformly Accelerated Motion is the motion of an object where the acceleration is constant.
A car starts from rest, that is, its initial speed is 0 m/s. It accelerates at 9 m/s². We can find the final speed after 240 m using the following kinematic equation.
v² = u² + 2 × a × s
v² = (0 m/s)² + 2 × (9 m/s²) × 240 m
v = 66 m/s
where,
- v is the final speed.
- u is the initial speed.
- a is the acceleration.
- s is the displacement.
A car starts from rest and accelerates at 9 m/s². After 240 m. the final speed is 66 m/s.
Learn more about Uniformly Accelerated Motion here: brainly.com/question/10178440
Light<span> refracts whenever it </span>travels<span> at an angle into a substance with a </span>different<span>refractive index (optical density). This change of direction is </span>caused<span> by a change in speed. For example, when </span>light travels<span> from air into water, it slows down, causing it to continue to travel at a </span>different<span> angle or direction.</span>
Answer:
719
Explanation:
Conversion
1 picometer (pm) is equivalent to
meter
1 micrometer is equivalent to
meter
To find the number of layers, we divide the overal leaf thickness by the thickness of one atom hence dividing tex]0.125 × 10^{-6}[/tex] meter by
meter we get that the number of sheets will be as follows

Therefore, they are approximately 719 sheets
Answer:
Time needed: 2.5 s
Distance covered: 31.3 m
Explanation:
I'll start with the distance covered while decelerating. Since you know that the initial speed of the car is 15.0 m/s, and that its final speed must by 10.0 m/s, you can use the known acceleration to determine the distance covered by
v2f=v2i−2⋅a⋅d
Isolate d on one side of the equation and solve by plugging your values
d=v2i−v2f2a
d=(15.02−10.02)m2s−22⋅2.0ms−2
d=31.3 m
To get the time needed to reach this speed, i.e. 10.0 m/s, you can use the following equation
vf=vi−a⋅t, which will get you
t=vi−vfa
t=(15.0−10.0)ms2.0ms2=2.5 s