The given equation has no solution when K is any real number and k>12
We have given that
3x^2−4x+k=0
△=b^2−4ac=k^2−4(3)(12)=k^2−144.
<h3>What is the condition for a solution?</h3>
If Δ=0, it has 1 real solution,
Δ<0 it has no real solution,
Δ>0 it has 2 real solutions.
We get,
Δ=k^2−144 here Δ is not zero.
It is either >0 or <0
Δ<0 it has no real solution,
Therefore the given equation has no solution when K is any real number.
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Answer:
the probability to flip a head is 50%
Step-by-step explanation:
I think.
Answer:
B 82 + 6x < 30-12x
Step-by-step explanation:
I think its b because it shows that Christian has more money and the deposits that he made.
Sorry if its wrong, i do 7th grade math
The answer is d actually I don’t know
