Answer:
1000g
Explanation:because the higher mass takes up heat.
1,38×10²² = 0,138×10²³
0,138×10²³ ----- 1,5g
6,02×10²³ ------ X
X = (1.5×6,02×10²³)/0,138×10²³
X = 65,435 g/mol
It's ZINC (Zn)
:•)
Answer:
Explanation:
Hello,
In this case, during titration at the equivalence point, we find that the moles of the base equals the moles of the acid:
That it terms of molarities and volumes we have:
Next, solving for the volume of lithium hydroxide we obtain:
Best regards.
Answer:
HCl(aq) + KOH(aq) ===> H2O(l) + KCl(aq)
Note the stoichiometry of the balanced equations shows us that HCl and KOH react in a 1:1 mole ratio. So, let us find moles of HCl and moles of KOH that are present:
moles HCl = 250.0 ml x 1 L/1000 ml x 0.25 mol/L = 0.06250 moles HCl
moles KOH = 200.0 ml x 1 L/1000 ml x 0.40 mol/L = 0.0800 moles KOH
You can see that there are more moles of KOH than there are of HCl, meaning that KOH is in excess and after neutralizing all of the HCl, the solution will be left with excess KOH making the pH > 7 = BASIC
Answer:
2H2S + 3O2 → 2SO2 + 2H2O
V(O2) = 48.4 L
p = 105 kPa = 1.036 atm
T = 190 + 273 = 463 K
Ideal gas law:
pV = nRT
n = \frac{pV}{RT}n=
RT
pV
R = 0.08206 L×atm/mol×K
n(O2) = \frac{1.036 \times 48.4}{0.08206 \times 463}=1.319 \; mol=
0.08206×463
1.036×48.4
=1.319mol
According to the reaction:
n(H2S) = \frac{2}{3}
3
2
n(O2) = \frac{2}{3} \times 1.319 = 0.8798 \;mol
3
2
×1.319=0.8798mol
V = \frac{nRT}{p} \\ V(H_2S) = \frac{0.8798 \times 0.08206 \times 463}{1.036}=32.26 \;LV=
p
nRT
V(H
2
S)=
1.036
0.8798×0.08206×463
=32.26L
Answer: 32.26 L
Explanation:
