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Maslowich
3 years ago
14

9. What type of bond is pictured in the image below?

Chemistry
1 answer:
mestny [16]3 years ago
8 0

Answer:

metallic bond

because this diagram is electron gas theory which shows metallic bond

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PAP Physical Studies<br><br> How can you remember the periodic table?
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What is the formula mass of MgO (how much does one mole of it weigh)
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The volume of the aquarium in our classroom is 1890 L. The density of seawater is 1.03g/cm^3. What is the mass of the water in o
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5 0
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15.0 moles of gas are in a 8.00 L tank at 22.3 ∘C∘C . Calculate the difference in pressure between methane and an ideal gas unde
leva [86]

Answer:

\Delta P=4.10atm

Explanation:

Hello!

In this case, since the ideal gas equation is used under the assumption of no interaction between molecules and perfectly sphere-shaped molecules but the van der Waals equation actually includes those effects, we can compute each pressure as shown below, considering the temperature in kelvins (22.3+273.15=295.45K):

P^{ideal}=\frac{nRT}{V}=\frac{15.0mol*0.08206\frac{atm*L}{mol*K}*295.45K}{8.00L}=45.5atm

Next, since the VdW equation requires the molar volume, we proceed as shown below:

v=\frac{8.00L}{15.0mol}=0.533\frac{L}{mol}

Now, we use its definition:

P^{VdW}=\frac{RT}{v-b} -\frac{a}{v^2}

Thus, by plugging in we obtain:

P^{VdW}=\frac{0.08206\frac{atm*L}{mol*K}*295.45K}{0.533mol/L-0.0430L/mol} -\frac{2.300L^2*atm/mol^2}{(0.533L/mol)^2}\\\\P^{VdW}=49.44atm-8.09atm\\\\P^{VdW}=41.4atm

Thus, the pressure difference is:

\Delta P=45.5atm-41.4atm\\\\\Delta P=4.10atm

Best regards!

6 0
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