Answer:- 38.2 g.
Solution:- The equation used for solving this type of calorimetry problems is:
where, q is the heat energy, m is mass, c is specific heat and delta T is the change in temperature.
Water temperature is increasing from 14.5 degree C to 50.0 degree C.
= 35.5 degree C
q is given as 5680 J and specific heat value is .
The equation could be rearranged for m as:
Let's plug in the values in it:
m = 38.2 g
So, the mass of water in the kettle is 38.2 g.
Answer:
0.18 mol
Explanation:
Given data
Step 1: Convert the mass of the solvent to kilograms
We will use the relationship 1 kg = 1,000 g.
Step 2: Calculate the moles of the solute
The molality is equal to the moles of solute divided by the kilograms of solvent. Then,
The molality of H₂SO₄ solution is 24.2 m.
<u>Explanation:</u>
We need to find the molality of sulfuric acid.
Mass of sulfuric acid = 785.6 g
Mass of water = 359 g
We have to find the moles of H₂SO₄ by using its mass and molar mass as,
Moles of H₂SO₄ =
= 8.7 moles
Mass of the solution in kg = = 0.359 kg
Molality =
=
= 24.2 m
So molality of the H₂SO₄ solution is 24.2 m.