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Montano1993 [528]
2 years ago
9

If Superman wants to slow down a fast car with speed 20 m/s and mass 1000 kg, how much force in N does he need to apply if he wa

nts to get it down to zero within 3.2 seconds?
Physics
1 answer:
saveliy_v [14]2 years ago
8 0

Answer:

Force of 6250N is required to slow down the body to zero.

Explanation:

Speed(V)=20m/s

Initial speed (u) =0m/s

Mass(M)=1000kg

Time(t)=3.2seconds

Using first equation of motion to find the acceleration of the body:

V=U + at

20m/s=0 + a*3.2s

Therefore, a=(20m/s)/3.2s

a=6.25m/s^2

To find the force required to stop the body or get it down to zero:

Force(F)=mass x acceleration

F=(1000kg)*(6.25m/s^2)

F=6250N.

Therefore a force of 6250N is required to slow it down.

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Coherent light of frequency 6.37×1014 Hz passes through two thin slits and falls on a screen 88.0 cm away. You observe that the
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Answer:

The distance between the two slits is 40.11 μm.

Explanation:

Given that,

Frequency f= 6.37\times10^{14}\ Hz

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Position of the third order y =3.10 cm

We need to calculate the wavelength

Using formula of wavelength

\lambda=\dfrac{c}{f}

where, c = speed of light

f = frequency

Put the value into the formula

\lambda=\dfrac{3\times10^{8}}{6.37\times10^{14}}

\lambda=471\ nm

We need to calculate the distance between the two slits

m\times \lambda=d\sin\theta

d =\dfrac{m\times\lambda}{\sin\theta}

Where, m = number of fringe

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Here, \sin\theta =\dfrac{y}{l}

Put the value into the formula

d=\dfrac{3\times471\times10^{-9}\times88.0\times10^{-2}}{3.10\times10^{-2}}

d=40.11\times10^{-6}\ m

d = 40.11\ \mu m

Hence, The distance between the two slits is 40.11 μm.

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2 years ago
A vector R is resolved into its components, Rx and Ry. If the ratio of is 2, what is the angle that the resultant makes with the
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A 3.5 kg object moving at 8.1 m/s in the positive direction of an x axis has a one-dimensional elastic collision with an object
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Answer:

So the mass of the second object M will be 1.951 kg    

Explanation:

We have given mass of the first object m_1=3.5kg and its velocity v_1=8.1m/sec

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From conservation of momentum we know that

Initial momentum = final momentum

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Answer:

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