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zaharov [31]
3 years ago
14

If you have any questions, let me know​

Physics
1 answer:
klasskru [66]3 years ago
6 0

Answer:

The red car would experience the greatest acceleration.

Explanation:

Newton says that Force equals mass times acceleration or F = ma

We get a = F/m

If we want the greatest acceleration or a, mass or m must be the lowest.

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A car is pulled with a force of 10,000 N. The car's mass is 1267 kg. But, the car covers 394.6 m in 15 seconds
Rasek [7]

F=m*a=>a=F/m=10000/1267=7.89 m/s²

d=v₀t+a't²/2<=>394.6=112.5*a'=>a'=3.5

a-a'=7.89-3.5=4.39 m/s²

This difference causes friction forces

We apply the second principle of dynamics: vector: F + N + G + Ff = ma (vector vectors, I can not here)

Scalar: Ox: F-Ff = ma

            Oy N-mg = 0

Ff = -ma+ F =-1267*7.89+10000=-8869+10000=1131 N

This frictional force (Ff) is opposite to the traction (F)


6 0
3 years ago
How are musical instruments grouped?
rosijanka [135]

A and B are equivalent.  That's one way instruments are often grouped. (the "sopranos", the "altos", the "bass")

C is another way instruments are often grouped; (the "woods", the "brass")

D is another way instruments are often grouped; (the "strings", the "percussions")

6 0
3 years ago
Read 2 more answers
The pressure in an automobile tire depends on the temperature of the air in the tire. When the air temperature is 25°C, the pres
12345 [234]

Answer:0.0704 kg

Explanation:

Given

initial Absolute pressure(P_1)=210+101.325=311.325

T_1=25^{\circ}\approx 298 K

V=0.025 m^3

T_2=50^{\circ}\approx 323 K

as the volume remains constant therefore

\frac{P_1}{T_1}=\frac{P_2}{T_2}

\frac{311.325}{298}=\frac{P_2}{323}

P_2=337.44 KPa

therefore Gauge pressure is 337.44-101.325=236.117 KPa

Initial mass m_1=\frac{P_1V}{RT_1}=\frac{311.325\times 0.025}{0.0287\times 298}

m_1=0.91 kg

Final mass m_2=\frac{P_2V}{RT_2}=\frac{311.325\times 0.025}{0.0287\times 323}

m_2=0.839

Therefore m_1-m_2=0.91-0.839=0.0704 kg of air needs to be removed to get initial pressure back

4 0
3 years ago
calculate the value of net force acting on given body?5N acting towards right &amp; 15N force acting towards left on the brick.(
lys-0071 [83]

Answer:

The net force acting on the body is 10N directed to the left.

Explanation:

   Magnitude of force to the right = 5N

   Magnitude of force to the left  = 15N

Net force acting on the object and in what direction;

Solution:

It is the vector sum of all forces acting on a body. This net force is the single force that will replace the forces acting on a body;

  For the problem;

   Net force  = Force to the left + Force to the right

 Let us take left to be negative and right to be positive;

    Force to the left  = -15N

    Net force  = -15N + 5N  = -10N

The net force acting on the body is 10N directed to the left.

4 0
3 years ago
How many atoms of Carbon (C) are in 3CO2
viva [34]

Answer:

in co2 there is one atom of carbon

Explanation:

8 0
3 years ago
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