Answer:
Work done, W =1520 J
Explanation:
We have,
The brakes on a bicycle apply 95 N of force to the wheels. When the brakes are applied, the bicycle comes to a stop in 16 m.
It is required to find the work done by the brakes on the wheels. We know that the product of force and displacement is equal to the work done. It is given by :
So, the work done by the brakes is 1520 J.
<h3><u>Answer;</u></h3>
1st drop; Motor
2nd drop; Electricity
A device that uses electricity and magnetism to create motion is called a <u>motor</u>. In a reverse process, a device that uses motion and magnesium can be used to create <u>electricity</u>.
<h3><u>Explanation</u>;</h3>
- <em><u>Motors are device which use electricity and magnetism to create motion.</u></em> They pass alternating current through opposing pairs of magnets to create a rotating magnetic field which creates a magnetic field in the rotor of a motor, making it to spin around.
- <em><u>Electric motors work in a reverse process by using motion and magnetism to generate electricity. </u></em>When a coil or loops of wire are exposed to a changing magnetic field, an electrical current arises or is induced.
<span>65W * 8h * 3600s/h = 1.9e6 J = 447 Cal </span>
Answer:
A) τ = 1,222 10⁻⁶ N m
, B) w = 0.24 rad / sec
, v = 2.88 10⁻³ m / s
Explanation:
Part A
We can get the torque
τ= F x r
bold are vector
τ = F r sin θ
Let's use according to Newton's law
F - W = 0
F = mg
τ = mg r sin θ
Let's reduce the magnitudes to the SI system
m = 12 ug = 12 10⁻⁶ kg
r = 12 mm = 12 10⁻³ m
Let's calculate
τ = 12 10⁻⁶ 9.8 12 10⁻³ sin 60
τ = 1,222 10⁻⁶ N m
Part B
Let's use Newton's law for rotational movement
τ = I α
The moment of inertia of the antero that we approximate as a particle is
τ = m r² α
α = τ / m r²
α = 1,222 10⁻⁶ / (12 10⁻⁶ (12 10⁻³)²)
α = 0.70718 10³ rad / s²
Angular velocity is
w = w₀ + α t
w = 0 + 0.70718 10³ 0.34 10⁻³
w = 0.24 rad / sec
Angular and linear variables are related.
v = w r
v = 0.24 12 10⁻³
v = 2.88 10⁻³ m / s