We can write the balanced equation for the galvanic cell by using the oxidation and reduction half-reactions. In the anode, Ni(s) is oxidized and produces aqueous Ni2+:
Ni(s) → Ni2+
while in the cathode, Cu2+ is reduced and deposits copper:
Cu2+ → Cu(s)
We now balance the charge of each reaction by adding electrons to the side of the equation with the greater charge:
Ni(s) → Ni2+ + 2 e-
Cu2+ + 2 e- → Cu(s)
Finally, we add the half-reactions to obtain the overall balanced equation for the galvanic cell:
Cu2+(aq) + Ni(s) → Ni2+(aq) + Cu(s)
The correct answer is
C.
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Answer:
b
Explanation:
Heterogeneous is a mixture of two or more things (phases)...the others are all one phase