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77julia77 [94]
3 years ago
10

Potassium bromide is an ionic compound. If you dissolve potassium bromide in water and add electricity, what will happen? It wil

l __________. Select one:
a. explode
b. become a covalent compound
c. allow ions to flow through the water
d. become an acid
Chemistry
2 answers:
ra1l [238]3 years ago
5 0

10/10 C is correct just did the same question.

Rom4ik [11]3 years ago
3 0
C. allow ions to flow through the water

KBr(s) = K⁺(aq) + Br⁻(aq)
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Hello there!

In this case, since this titration is carried out via the following neutralization reaction:

HONH_2+HCl\rightarrow HONH_3^+Cl^-

We can see the 1:1 mole ratio of the acid to the base and also to the resulting acidic salt as it comes from the strong HCl and the weak hydroxylamine. Thus, we first compute the required volume of HCl as shown below:

V_{HCl}=\frac{22.0mL*0.200M}{0.15M}=29.3mL

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0.0220L*0.200mol/L=0.0044mol

And therefore the concentration of the salt at the equivalence point is:

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HONH_3^++H_2O\rightleftharpoons H_3O^++HONH_2

Whereas the equilibrium expression is:

Ka=\frac{[H_3O^+][HONH_2]}{[HONH_3^+]}

Whereas Ka is computed by considering Kw and Kb of hydroxylamine:

Ka=\frac{Kw}{Kb}=\frac{1x10^{-14}}{9.10x10^{-9}}  \\\\Ka=1.10x10^{-6}

So we can write:

1.10x10^{-6}=\frac{x^2}{0.0858-x}

And neglect the x on bottom to obtain:

1.10x10^{-6}=\frac{x^2}{0.0858}\\\\x=\sqrt{1.10x10^{-6}*0.0858}=3.07x10^{-4}M

And since x=[H3O+] we obtain the following pH:

pH=-log(3.07x10^{-4})\\\\pH=3.513

Regards!

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3 years ago
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