Question

(3p3q)^3/4 What is the expression in radical form?

Answer 1

Answer:

$p^2\sqrt[4]{27pq^3}$

Step-by-step explanation:

$(3p^3q)^\frac{3}{4}$

To get radical form , remove the fractional exponent

$(a^m)^n=a^{mn}$

multiply the exponent 3/4 inside the parenthesis

$3^\frac{3}{4} p^{3 \cdot \frac{3}{4}} q^\frac{3}{4}$

$3^\frac{3}{4} p^{\frac{9}{4}} q^\frac{3}{4}$

$\sqrt[4]{27} \cdot p^2\sqrt[4]{p} \cdot \sqrt[4]{q^3}$

$p^2\sqrt[4]{27pq^3}$

Answer 2

The answer is 4/27p9q3  Hope I helped!